Answer : The mass of potassium hypochlorite is, 4.1 grams.
Explanation : Given,
pH = 10.20
Volume of water = 
The decomposition of KClO will be :

Now the further reaction with water
to give,

First we have to calculate the pOH.

Now we have to calculate the
concentration.
![pOH=-\log [OH^-]](https://tex.z-dn.net/?f=pOH%3D-%5Clog%20%5BOH%5E-%5D)
![3.8=-\log [OH^-]](https://tex.z-dn.net/?f=3.8%3D-%5Clog%20%5BOH%5E-%5D)
![[OH^-]=1.58\times 10^{-4}M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D1.58%5Ctimes%2010%5E%7B-4%7DM)
Now we have to calculate the base dissociation constant.
Formula used : 
Now put all the given values in this formula, we get :

Now we have to calculate the concentration of
.
The equilibrium constant expression of the reaction is:
![K_b=\frac{[OH^-][HClO]}{[ClO^-]}](https://tex.z-dn.net/?f=K_b%3D%5Cfrac%7B%5BOH%5E-%5D%5BHClO%5D%7D%7B%5BClO%5E-%5D%7D)
As we know that, ![[OH^-]=[HClO]=1.58\times 10^{-4}M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D%5BHClO%5D%3D1.58%5Ctimes%2010%5E%7B-4%7DM)
![2.5\times 10^{-7}=\frac{(1.58\times 10^{-4})^2}{[ClO^-]}](https://tex.z-dn.net/?f=2.5%5Ctimes%2010%5E%7B-7%7D%3D%5Cfrac%7B%281.58%5Ctimes%2010%5E%7B-4%7D%29%5E2%7D%7B%5BClO%5E-%5D%7D)
![[ClO^-]=0.0999M](https://tex.z-dn.net/?f=%5BClO%5E-%5D%3D0.0999M)
Now we have to calculate the moles of
.


As we know that, the number of moles of
are equal to the number of moles of KClO.
So, the number of moles of KClO = 0.0449 mole
Now we have to calculate the mass of KClO.


Therefore, the mass of potassium hypochlorite is, 4.1 grams.