Log7 (x+3) - log7 (x-3) = 1
log7 [(x+3) / (x-3)] = 1
raise both sides to power of 7
(x+3) / (x-3) = 7
7x – 21 = x + 3
6x = 24
x = 4
Answer:
y=-1/2x+3/2
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(-1-1)/(5-1)
m=-2/4
m=-1/2
y-y1=m(x-x1)
y-1=-1/2(x-1)
y=-1/2x+1/2+1
y=-1/2x+1/2+2/2
y=-1/2x+3/2
Answer:
option B
Step-by-step explanation:
Given in the question a complex fraction
<h3>Step1</h3>
To divide complex numbers, you must multiply by the conjugate. To find the conjugate of a complex number all you have to do is change the sign between the two terms in the denominator.
<h3>Step2</h3>
Distribute (or FOIL) in both the numerator and denominator to remove the parenthesis.
<h3>Step3</h3>
Simplify the powers of i, specifically remember that i² = –1.
<h3>Step4</h3>
<h3>Step5</h3>
simply
The answer is b)04 I did this on my test and got it correct
Answer:
10 SENIORS
Step-by-step explanation:
x=# of seniors
y=# of juniors
x+y=23, x=2y-7
- plug the value of x in the second equation into the first
- (2y-7)+y=23
- Remove parentheses
- 2y-7+y=23
- Combine like terms
- 3y-7=23
- Add 7 to BOTH sides
- 3y=30
- divide BOTH sides by 3
- 3y/3=30/3
- y=10
- There are 10 juniors in the class
- FINAL STEPS
- Plug y (which is 10) into the first equation
- x+y=23
- x+10=23
- subtract 10 from BOTH sides
- x=13
- Since X equals the number of seniors, there are 10 seniors in the class
