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Sladkaya [172]
2 years ago
12

Help me on this :( pls

Mathematics
2 answers:
Doss [256]2 years ago
4 0
X = 12 dhucdjvdsiksdjfbhfud gimme brainliest
vampirchik [111]2 years ago
4 0

Answer:

X=12 this is the answer and hope it helps :) and if u want it simplified u can simplify it

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A survey was conducted that asked 1003 1003 people how many books they had read in the past year. results indicated that x overb
kirill115 [55]
The confidence interval is

10.5\pm1.35 = (9.15, 11.85).  This means that we can be 99% confident that the mean number of books people read lies between 9.15 and 11.85.

To find the confidence interval, we first find the z-score associated with it:

Convert 99% to a decimal:  0.99
Subtract from 1:  1-0.99=0.01
Divide by 2:  0.01/2 = 0.005
Subtract from 1:  1-0.005 = 0.995

Using a z-table (http://www.z-table.com) we see that this is associated with a z-score between 2.57 and 2.58.  Since both are equally far from this value we will use 2.575.

We calculate the margin of error using

ME=z*\frac{s}{\sqrt{n}}
\\
\\=2.575*\frac{16.6}{\sqrt{1003}}=1.35

This means that the confidence interval is
10.5\pm1.35

The lower limit is given by 10.5-1.35 = 9.15.
The upper limit is given by 10.5+1.35 = 11.85
5 0
3 years ago
Worth 75 points!! Need help with calculus
Keith_Richards [23]
The correct answer is:

2u-v=7(5i-3j)

Therefore, 5, and 3 go inside the box.
4 0
3 years ago
Geometry help... ...........
oksian1 [2.3K]
Angle 3 is 78 degrees. same as angle 5.
8 0
3 years ago
Read 2 more answers
I'LL GIVE BRAINLIST<br><br> Select all the rates that are unit rates.
Alex Ar [27]

Answer:

B and D

Step-by-step explanation:

5 0
2 years ago
Assuming the amount of money college students spend on text books each semester is symmetrical with a mean of 500 and a standard
TiliK225 [7]

16% percent of the students paid MORE than Jane.

The mean(μ) of money spent on textbooks is 500

The standard deviation(σ) of money spent on textbooks is 50

Money paid by Jane for her books is $550

We will use this formula,

Ζ=x-μ/σ

To find: the percentage of students paid MORE than Jane for the textbooks

P(X > 550)=?

Solution:

P(X > 550)=1-P(X≤550)

=1-P(Ζ≤\frac{550-500}{50} )

=1-P(Ζ≤ 1)

=1-0.8413

=0.1587

≈16%

Therefore, 16% percent (approx) of the students paid MORE than Jane.

Learn more about mean and standard deviation here brainly.com/question/4388715

#SPJ4

3 0
2 years ago
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