Can Anyone help me with this question?!

When deriving the quadratic formula by completing the square, what expression can be added to both sides of the

liubo4ka [24]

Answer:

The element you add is $b^2 / 4a$

Step-by-step explanation:

The element you add is $b^2 / 4a$

Remember that

$a x^2 + bx +c \\= a ( x^2 +(b/a)x ) + c$

So, in order to complete the square you add $(b/2a)^2$

But when you multiply times $a$ you get

$b^2 / 4a$

7 0

3 years ago

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Instructions: Find the missing side lengths. Leave your answers as radicals in simplest form.

ivanzaharov [21]

Answer:

x = 6

y = 3

Step-by-step explanation:

Give triangle is a right triangle.

By applying sine ratio in the given triangle,

sin(60)° = $\frac{\text{Opposite side}}{\text{Hypotenuse}}$

$\frac{\sqrt{3}}{2}=\frac{3\sqrt{3}}{x}$

x = 6

Now we take the cosine ratio in the given triangle,

cos(60)° = $\frac{\text{Adjacent side}}{\text{Hypotenuse}}$

$\frac{1}{2}=\frac{y}{x}$

y = $\frac{x}{2}$

y = $\frac{6}{2}=3$

Therefore, x = 6 and y = 3 will be the answer.

3 0

3 years ago

Determine if the sequence below is arithmetic or geometric and determine the common difference / ratio in simplest form. 4,9,14,

scZoUnD [109]

Answer:

It is an arithmetic sequence and the common difference is 5

Step-by-step explanation:

4+5 = 9; 9+5=14 (adding is arithmetic, multiplying is geometric)

7 0

2 years ago

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Alina drew a model of a square pyramid. The dimensions of the model are shown in the diagram. pls don't answer with links

Romashka [77]

Answer:

C

Step-by-step explanation:

Volume of a pyramid = 1/3 base area * height

= 1/3 (8 * 10)(12)

6 0

2 years ago

(cosxtanx-tanx+2cosx-2)/tanx+2=cosx-1<br> can someone show me how to prove this?

uysha [10]

Answer:

See detail below.

Step-by-step explanation:

A word of caution before getting to the actual problem: I believe there is an important set of brackets missing in the original post. The expression on the left hand side should be:

(cosxtanx-tanx+2cosx-2)/(tanx+2)

Without the brackets, it is left unclear whether the denominator is just tanx or tanx+2. I recommend to use brackets wherever any doubt could arise.

Now to the actual problem: \we can make the following transformations on the left hand side:

$\frac{\cos x \tan x + 2\cos x -2}{\tan x +2}=\frac{\cos x \frac{\sin x}{\cos x} + 2\cos x -2}{\frac{\sin x +2\sin x}{\cos x} }=\\=\frac{\cos x \sin x - \sin x + 2\cos^2 x - 2\cos x}{\sin x + 2\cos x}=\\=\frac{\cos x \sin x +2\cos^2 x }{\sin x + 2\cos x}-1=\\=\cos x -1$

which is shown to be the same as the right hand side, which was to be shown.

7 0

3 years ago