Answer:
633
Step-by-step explanation:
We have the equation
![15+102[12-(12-3*2)]+6\\\\15+102[12-(12-6)]+6\\\\15+102[12-(6)]+6\\\\15+102[6]+6\\\\15+612+6\\\\633](https://tex.z-dn.net/?f=15%2B102%5B12-%2812-3%2A2%29%5D%2B6%5C%5C%5C%5C15%2B102%5B12-%2812-6%29%5D%2B6%5C%5C%5C%5C15%2B102%5B12-%286%29%5D%2B6%5C%5C%5C%5C15%2B102%5B6%5D%2B6%5C%5C%5C%5C15%2B612%2B6%5C%5C%5C%5C633)
Answer:42/3
=3/42
Step-by-step explanation:
Answer:
6
Step-by-step explanation:
First, we can expand the function to get its expanded form and to figure out what degree it is. For a polynomial function with one variable, the degree is the largest exponent value (once fully expanded/simplified) of the entire function that is connected to a variable. For example, x²+1 has a degree of 2, as 2 is the largest exponent value connected to a variable. Similarly, x³+2^5 has a degree of 2 as 5 is not an exponent value connected to a variable.
Expanding, we get
(x³-3x+1)² = (x³-3x+1)(x³-3x+1)
= x^6 - 3x^4 +x³ - 3x^4 +9x²-3x + x³-3x+1
= x^6 - 6x^4 + 2x³ +9x²-6x + 1
In this function, the largest exponential value connected to the variable, x, is 6. Therefore, this is to the 6th degree. The fundamental theorem of algebra states that a polynomial of degree n has n roots, and as this is of degree 6, this has 6 roots
Answer:
OA and OC hope that helps :)
