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3 years ago

Alfred drove 114 miles in 3 hours. If Alfred drove at a constant rate, how fast did he drive in miles per hour?

Mathematics

2 answers:

Andreyy893 years ago

6 0

38 miles per hour.......

schepotkina [342]3 years ago

4 0

You would divide 114 ( the total miles) by 3 ( the allotted amount of time) which would give you the mph . 114/3 = 38 , so Alfred would’ve driven 38 mph or miles per hour.

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What is the distance, to the nearest hundredth, from (6, 5) to (−3, −8)?

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Answer:

15.81

Step-by-step explanation:

Use the distance formula:

So the distance formula for two given points is

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=sqrt((-9)^2 +(-13)^2 )

=sqrt(81+169)

=sqrt(250)

=15.81

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The price of a car is 15,000. John got a 20% discount. Find how much is the discount and how much he will pay after the discount

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Answer:

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Step-by-step explanation:

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3 years ago

Use the distributive property to factor the expression. 15x + 6

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3 years ago

the perimeter of football field in a rectangular form of a certain school is 296cm if the breath is2/3 of the length find the le

Pani-rosa [81]

Answer:

L = 29.6 cm

Step-by-step explanation:

Let Length be L and Breadth be B

Condition 1:

$2(Length)+2(Breadth) = Perimeter$

Where Perimeter = 296 cm

=> 2L + 2B = 296

=> 2(L+B) = 296

Dividing both sides by 2

=> L + B = 148 ------------------(1)

Condition 2:

=> B = $\frac{2}{3} L$ -------------------------(2)

Putting Equation 2 in 1

=> L + $\frac{2}{3} L$ = 148

Multiplying both sides by 3

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6 0

3 years ago

Read 2 more answers

Graph the data in the table. Which kind of function best models the data? Write an equation to model the data. quadratic; y = 2.

Oksanka [162]

Answer:

Option (1)

Step-by-step explanation:

x -2 -1 0 1 2

y 10 2.5 0 2.5 3.0

Ist difference,

$d_1=y_2-y_1$

$=2.5-10=-7.5$

$d_2=y_3-y_2$

$=0-2.5$

= -2.5

$d_3=y_4-y_3$

$=2.5-0$

= 2.5

$d_4=y_5-y_4$

$=10.0-2.5$

= 7.5

2nd difference,

$x_1=d_2-d_1$

$=-2.5+7.5$

= 5

$x_2=d_3-d_2$

$=2.5+2.5$

= 5

$x_3=d_4-d_3$

$=7.5-2.5$

= 5

Since 2nd difference is common, given table represents a quadratic equation.

Let the equation is,

y = ax²+ bx + c

For a point (0, 0) passing through the quadratic equation,

0 = c

Therefore, quadratic equation is y = ax² + bx

Since ordered pair (-1, 2.5) passes through the graph of the function,

2.5 = a(-1)² + b(-1)

a - b = 2.5 ------(1)

For another point (1, 2.5)

2.5 = a(1)² + b(1)

a + b = 2.5 ------(2)

By adding equations (1) and (2),

2a = 5

a = 2.5

and from equation (2)→ y = 0

Therefore, equation of the quadratic function given in the table is y = 2.5x²

Option (1) is the answer.

8 0

3 years ago