The last one best models the situation
Nothing is attached I cannot
6,12,18,24,30,36,42,48,54,60,66,72,78,84,90,96,
Your function f(x)=(x^(1/3))(x+4)
What your going to want to do first is calculate your first derivative.
You will want to use both the power rule and the product rule.
f '(x)=(x+4)/x^(2/3)+x^(1/3)
f '(x)=4/3(x^(-2/3))(x+1)
Now find the critical numbers
4/3(x^(-2/3))=0 x+1=0
x=0, x=-1
Now plug numbers on the intervals (-infinity, -1),(-1,0) and (0,infinity) into the derivative of your function. The numbers I would choose are -2, -1/2 and 1.
Since f '(-2) is negative, f '(-1/2) is positive and f '(1) is positive, (-1,-3) and (1,5) are relative extrema. This means that the function f(x)=(x^(1/3))(x+4) is increasing on the interval (-1,0) U (0,infinity).
Answer:
y=2 is the correct ans.
here, tge equn of st line passing through the point (3,2) and is also parallel to y axis.
we have, equn of st line parallel to y xaus is y= b
so , the equn of st line passing through the point (3,2) is y= 2 (where 2 is likely to b).
