Select the correct answer.
2 answers:
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Think of the two pieces together as a single cone of height 19, and its volume.
Then think of only the upper piece as a cone, and find its volume.
The volume of the frustum is the total volume minus the volume of the upper piece.
The volume of a cone is:
Total volume:
Volume of upper cone:
Volume of frustum:
Then think of only the upper piece as a cone, and find its volume.
The volume of the frustum is the total volume minus the volume of the upper piece.
The volume of a cone is:
Total volume:
Volume of upper cone:
Volume of frustum:
Answer:
32°
Step-by-step explanation:
Given:
∠DMQ = 58º
In this circle, the radius is DM. Since AD is tangent to the circle M, at point D, and the angle between a tangent and a radius is 90°
Therefore, ∠MDQ = 90°
The total angle in a triangle is 180°. Since we have the values of ∠MDQ and ∠DMQ, ∠DQM will be calculated as:
180 = ∠DMQ + ∠MDQ + ∠DQM
Solving for ∠DQM, we have:
∠DQM = 180 - ∠DMQ - ∠MDQ
∠DQM = 180 - 90 - 58
∠DQM = 32°
The measure of ∠DQM is 32°
Answer:
First, I think the right formula is:
A) We first derive the formula given above:
V'(t) represent the drain rate of the tank volume.
B) the units is: gallons/time
C) at V'(10) = 100000/60 = 1666.66 gallons/time.
because the formula V'(t) is constant so it doesn't depend of time.