Answer:
answer is first option

wherein, a = 1, b = -3, c = -5
Answer:
39
Step-by-step explanation:
Answer:
- The value of PR is 21 ft.
Step-by-step explanation:
<u>We know that:</u>
- 3(PQ + QT + TP) = PR + RS + SP
- PQ = 7 ft.
- QT = 4 ft
- RS = 12 ft.
<u>Work:</u>
- 3(PQ + QT + TP) = PR + RS + SP
- => 3(7 + 4 + TP) = PR + 12 + SP
- => 21 + 12 + 3TP = PR + 12 + SP
- => 21 + 3TP = PR + SP
- => 21 + SP = PR + SP [3TP = SP]
- => 21 = PR
Hence, <u>the value of PR is 21 ft.</u>
Hoped this helped.

Answer:
7.96 ft
Step-by-step explanation:
Given;
Length of ramp L = 8 ft
Angle with the horizontal (ground) = 6°
Applying trigonometry;
With the length of ramp as the hypothenuse,
The horizontal distance d as the adjacent to angle 6°
Since we want to calculate the adjacent and we have the hypothenuse and the angle. We can apply cosine;
Cosθ = adjacent/hypothenuse
Substituting the values;
Cos6° = d/8
d = 8cos6°
d = 7.956175162946
d = 7.96 ft
The building is 7.96ft away from the entry point of the ramp.