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astra-53 [7]
3 years ago
11

What could cause the graph to be misleading?

Mathematics
1 answer:
Andrew [12]3 years ago
6 0
What could cause the graph to be miss leading because on the first week they worked zero hours but then for the second week they worked for eight hours but then soon on the third week they worked for four hours then on the fourth week they worked for sixteen hours.
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Olk-onm <br> Find the value of u.
damaskus [11]

Answer:

olk 69 -_-

Step-by-step explanation:

5 0
3 years ago
What is the measure of angle R?
tigry1 [53]

Option B:

25 degrees

Solution:

Given data in triangle PQR,

The side opposite to angle P is p.

The side opposite to angle Q is q.

The side opposite to angle R is r.

q = 36, r = 20, angle Q = 50°.

<u>To find the measure of angle R:</u>

Using law of sine,

$\frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C}

$\Rightarrow\frac{p}{\sin P}=\frac{q}{\sin Q}=\frac{r}{\sin R}

Take only two sides.

$\Rightarrow\frac{q}{\sin Q}=\frac{r}{\sin R}

Substitute the given values.

$\Rightarrow\frac{36}{\sin 50^\circ}=\frac{20}{\sin R}

Do cross multiplication.

\Rightarrow36\times\sin R = \sin50^\circ\times20

sin 50° = 0.766

\Rightarrow36\times\sin R = 0.766\times20

\Rightarrow36\times\sin R = 15.32

$\Rightarrow\sin R = \frac{15.32}{36}

$\Rightarrow\sin R = 0.4255

$\Rightarrow R = \sin^{-1}(0.4255)

⇒ R = 25.18°

⇒ R = 25° (approximately)

Option B is the correct answer.

Hence the measure of angle R is 25 degrees.

3 0
3 years ago
Desmond deposits $50 into a savings account every month at an annual interest rate of
joja [24]

Given:

Desmond deposits $ 50 monthly.

Yearly he deposits = $50×12 = $ 600

Rate of interest compounded monthly = 4.7%

To find the amount he will receive after 10 years and the rate of change the value of his account after 10 years.

Formula

A = P(1+\frac{r}{(n)(100)} )^{nt}

where,

A be the final amount

P be the principal

r be the rate of interest

t be the time and

n be the number of times the interest is compounded.

Now,

Taking,

P = 600, r = 4.7, n = 12, t = 10 we get,

A = 600(1+\frac{4.7}{(12)(100)}) ^{(12)(10)}

or, A = 600(1.0039)^{120}

or, A = 959.1

Now,

At starting he has $ 600

At the end of 10 years he will be having $ 959.1

So,

The amount of change in his account = $ (959.1-600) = $ 359.1

Therefore the rate of change = (\frac{359.1}{600} )(100) %

= 59.85%

Hence,

a) His account will contain $ 959.1 after 10 years.

b) The rate of change in his account is 59.85% after 10 years.

7 0
3 years ago
4 1/4 divided by 2/7<br><br> (x+8)-(3x- 5)<br><br> Explain how you got the answer!!!!!
Dmitry_Shevchenko [17]

Turn it to improper fractions.

4 1/4 divided by 2/7

Divide them.

17/4 divided by 2/7

17      2     17 x 7

--- ÷  --- = --------- = 119/8 OR 14 7/8

4       7      4 x 2

-----------------------------------------------------

Distribute to take out the parentheses.

(x + 8) - (-3x - 5)

Combine like terms.

x + 8 + 3x + 5

Answer.

4x + 13

8 0
3 years ago
First, rewrite 9/10 and 23/25 so that they have a common denominator.
MAVERICK [17]
The cheap answer is, well, all we do is, grab the denominator of one and multiply the other by it, top and bottom, and grab the denominator of the other, and multiply the first one by that one too, that way, both will have the same denominator, and then you can simply check the numerator to see who's larger, let's do so.

\bf \cfrac{9}{\boxed{10}}\qquad \qquad \cfrac{23}{\boxed{25}}&#10;\\\\\\&#10;\cfrac{9\cdot \boxed{25}}{10\cdot \boxed{25}}\implies \cfrac{225}{250}\qquad \qquad \qquad \cfrac{23\boxed{10}}{25\cdot \boxed{10}}\implies \cfrac{230}{250}\\\\&#10;-------------------------------\\\\&#10;\textit{so, which is larger then?}\qquad \cfrac{225}{250}~or~\cfrac{230}{250}?

surely you can tell.
3 0
3 years ago
Read 2 more answers
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