Plug 8 into the equation and divide it by that equation but with 5 plugged in
According to the graph given, and using it's concept, it is found that the initial value of the domain is of 0.
The <em>domain</em> of a function is the <u>set that contains all possible input values</u>.
- In a graph, it is <u>represented by the values of x</u>, which is the horizontal axis.
In the graph given in this problem, the function is <u>defined for x between 0 and 2</u>, that is, the <em>domain </em>is [0,2], hence, the initial value of the domain is of 0.
To learn more about domain, you can take a look at brainly.com/question/25897115
The <u>circle</u> is best described as all the points that are the same distance from a single point as its center.
distance between the midpoint and the border of circle are called <u>radius of circle.</u>
because a circle is special type of ellipse
to get the equation of any straight line we only need two points off of it, hmmm let's use P and Q here and then let's set the equation in standard form, that is
standard form for a linear equation means
• all coefficients must be integers, no fractions
• only the constant on the right-hand-side
• all variables on the left-hand-side, sorted
• "x" must not have a negative coefficient
![(\stackrel{x_1}{6}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{2}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{2}-\stackrel{y1}{0}}}{\underset{run} {\underset{x_2}{3}-\underset{x_1}{6}}}\implies \cfrac{2}{-3}\implies -\cfrac{2}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-\cfrac{2}{3}}(x-\stackrel{x_1}{6})](https://tex.z-dn.net/?f=%28%5Cstackrel%7Bx_1%7D%7B6%7D~%2C~%5Cstackrel%7By_1%7D%7B0%7D%29%5Cqquad%20%28%5Cstackrel%7Bx_2%7D%7B3%7D~%2C~%5Cstackrel%7By_2%7D%7B2%7D%29%20~%5Chfill%20%5Cstackrel%7Bslope%7D%7Bm%7D%5Cimplies%20%5Ccfrac%7B%5Cstackrel%7Brise%7D%20%7B%5Cstackrel%7By_2%7D%7B2%7D-%5Cstackrel%7By1%7D%7B0%7D%7D%7D%7B%5Cunderset%7Brun%7D%20%7B%5Cunderset%7Bx_2%7D%7B3%7D-%5Cunderset%7Bx_1%7D%7B6%7D%7D%7D%5Cimplies%20%5Ccfrac%7B2%7D%7B-3%7D%5Cimplies%20-%5Ccfrac%7B2%7D%7B3%7D%20%5C%5C%5C%5C%5C%5C%20%5Cbegin%7Barray%7D%7B%7Cc%7Cll%7D%20%5Ccline%7B1-1%7D%20%5Ctextit%7Bpoint-slope%20form%7D%5C%5C%20%5Ccline%7B1-1%7D%20%5C%5C%20y-y_1%3Dm%28x-x_1%29%20%5C%5C%5C%5C%20%5Ccline%7B1-1%7D%20%5Cend%7Barray%7D%5Cimplies%20y-%5Cstackrel%7By_1%7D%7B0%7D%3D%5Cstackrel%7Bm%7D%7B-%5Ccfrac%7B2%7D%7B3%7D%7D%28x-%5Cstackrel%7Bx_1%7D%7B6%7D%29)
![\stackrel{\textit{multiplying both sides by }\stackrel{LCD}{3}}{3(y-0)~~ = ~~3\left( -\cfrac{2}{3}(x-6) \right)}\implies 3y=-2(x-6) \\\\\\ 3y=-2x+12 \implies \stackrel{a}{2} x+\stackrel{b}{3} y=12](https://tex.z-dn.net/?f=%5Cstackrel%7B%5Ctextit%7Bmultiplying%20both%20sides%20by%20%7D%5Cstackrel%7BLCD%7D%7B3%7D%7D%7B3%28y-0%29~~%20%3D%20~~3%5Cleft%28%20-%5Ccfrac%7B2%7D%7B3%7D%28x-6%29%20%5Cright%29%7D%5Cimplies%203y%3D-2%28x-6%29%20%5C%5C%5C%5C%5C%5C%203y%3D-2x%2B12%20%5Cimplies%20%5Cstackrel%7Ba%7D%7B2%7D%20x%2B%5Cstackrel%7Bb%7D%7B3%7D%20y%3D12)
Complete question is;
If Pablo invests $4200 for 3 years and earns $630
A) what is the simple interest rate?
B) Pablo’s goal is to have $5000 after 4 years. Is it possible with a rate of 6%? Explain.
Answer:
A) Rate = 5%
B) Yes, it is possible for him to earn $5000 after 4 years with an interest rate of 6%
Step-by-step explanation:
A) Formula for interest is;
i = PRT
We are given;
i = 630
P = 4200
T = 3
Making R the subject;
R = i/PT
R = 630/(4200 × 3)
R = 0.05
This is 5%
B) Formula for value of principal after interest period is;
A = P(1 + RT)
P = 4200
R = 6% = 0.06
T = 4 years
Thus;
A = 4200(1 + (0.06 × 4))
A = $5208
Thus, it is possible for him to earn $5000 after 4 years with an interest rate of 6%