Since the sixth term is 1215 and the 5th term is 405, we know each term is 3 times more than the last.
Let 'n' represent the first term, then the sum of the first 9 terms can be written as:
n+3n+9n+27n+81n+243n+729n+2187n+6561n
which sinplifies to 9841n
since each term is 3 times the last, the first term must be 405 divided by 3, 4 times in total, which is 5
Now subsitute 'n' for 5, and we get 9841(5)
which is 49205 which is the answer.
Hope this helps
Answer:
C
Step-by-step explanation:
Each of the tables is a linear relationship. Linear relationships increase or decrease steadily by adding or subtracting a constant. Table A increases by 5. Table B decreases by 2. Table C doesn't change. Table D increase by 4.
A "no change" means the y values never change. The constant is 0 and is a horizontal line. Table C is the solution.
Answer:
79 = 13+15+24+ missing side. 79 = 52 + missing side
1) y=53
2)53
21 is 2 thirds of 32 so you add them together and get 53. Also Y=Cost of last years trip which we determined is $53
