19/2 - 11/2 as an improper fraction

1 answer:

rjkz [21]2 years ago

8 0

Answer:9 1/2 and 5 1/2

I hope that’s what your looking for

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docker41 [41]

Answer:

(a) fave = 8

(b) c = 64/9

Step-by-step explanation:

(a) The average value of the function is its integral over the interval, divided by the width of the interval.

$f_{ave}=\displaystyle\frac{1}{16-0}\int_0^{16} {3x^{\frac{1}{2}}} \, dx=\left.\frac{x^{3/2}}{8}\right|_0^{16}=8$

(b) We want ...

f(c) = 8

3√c = 8 . . . . . use f(c)

√c = 8/3 . . . . . divide by 3

c = (8/3)² . . . . square

c = 64/9

(c) c ≈ 7.111

7 0

3 years ago

valentinak56 [21]

Answer:

504

Step-by-step explanation:

In the attached file

Hope it helps

4 0

3 years ago

german

Using linear function concepts, it is found that:

a) It costs $0.1 for each kilowatt hour of electricity used in excess of 250 kWh.
b) f(90) = 46.6, which is the cost of 340 kWh of consumption in a month.

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A <em>linear function </em>has the format given by:

$y = mx + b$

In which:

m is the slope, which is the rate of change, that is, how much y changes when x changes by 1.
b is the y-intercept, which is the value of y when x = 0.

The equation for the cost of h kilowatt hours (kWh) of electricity used in excess of 250 kWh is of:

$C = f(h) = 37.6 + 0.1h$