Answer: See attached table
Step-by-step explanation:
![\begin{table}[]\begin{tabular}{lllll} & & & & \\ & & & & \\ & & & & \\ & & & & \end{tabular}\end{table}](https://tex.z-dn.net/?f=%5Cbegin%7Btable%7D%5B%5D%5Cbegin%7Btabular%7D%7Blllll%7D%20%26%20%20%26%20%20%26%20%20%26%20%20%5C%5C%20%26%20%20%26%20%20%26%20%20%26%20%20%5C%5C%20%26%20%20%26%20%20%26%20%20%26%20%20%5C%5C%20%26%20%20%26%20%20%26%20%20%26%20%5Cend%7Btabular%7D%5Cend%7Btable%7D)
+---+---+---+
| 1 | 8 | 2 |
+---+---+---+
| 6 | 4 | 2 |
+---+---+---+
| 5 | 0 | 7 |
+---+---+---+
<u>Proofs:</u>
First row: 1+6+5 = 12
Second row: 8+4+0 = 12
Third row: 2+2+7 = 12
First column: 1+8+2 = 12
Second column: 6+4+2 = 12
Third column: 5+0+7 = 12
Diagonal starting from top left to bottom right: 1+4+7 = 12
Diagonal staring from top right to bottom left: 2+4+5 = 12
Answer:
3/24= 33/264
2/9= 12/54
4/5= 32/40
8/9= 16/18
42/18= 7/3
32/12= 8/3
Step-by-step explanation:
You have to use common factors and denominators to match numbers. VERY COMPLICTED! Hope this helps!
<span> the answer is 0.66666666666 </span>
Answer:
(a) ∠DAB = 59°
(b) ∠A = 135°
(c) ∠A = 99°
Step-by-step explanation:
<u>Theorem</u>: If a quadrilateral is inscribed inside a circle, then the opposite angles of the quadrilateral are SUPPLEMENTARY.
So, here in the given figures:
(1) ∠DCB + ∠DAB = 180° (as opposite angles are supplementary)
⇒∠DAB = 180° - 121° = 59°
or, ∠DAB = 59°
(2) ∠DCB + ∠DAB = 180° (as opposite angles are supplementary)
⇒(3x+6) + (x+2) = 180° or, 4x = 180 - 8 = 172
⇒ x = 172/4 = 43, or x = 43
So, ∠A = (3x+6) = 3(43) + 6 = 135°
(3) (28) + (x) = 180°
or, x = 180 - 28 = 152
So, ∠A = (x- 36) = 135 - 36 = 99°
(4)
The square root of 81 is 9. Therefore, the positive square root of 81 is positive 9.
Hope this helps!
