3 years ago

How do I graph this someone plz tell me.

1 answer:

7 0

Easy. your starting point is going to be at -2 on the y-axis. then from that point (-2) you're going to go down 1 and then over 2. then draw a straight line through those two points. The line should be a negative line.

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Scilla [17]

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$\large \boxed{\text{22.07 m}}$

Step-by-step explanation:

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V = ⁴/₃πr³

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$\begin{array}{rcl}45001 & = & \dfrac{4}{3} \pi r^{3}\\\\33750 & = &\pi r^{3}\\10740 & = &r^{3}\\r & = & \textbf{22.07 m}\\\end{array}\\\text{The radius of the great circle is $\large \boxed{\textbf{22.07 m}}$}$

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nexus9112 [7]

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IrinaK [193]

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notka56 [123]

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