F(x) = (1/2)x + 4
Plug y in for f(x).
y = (1/2)x + 4
Swap x and y.
x = (1/2)y + 4
Solve the equation for y =.
Subtract 4 from both sides.
x - 4 = (1/2)y
Multiply each term 2.
2x - 8 = y
Plug f^-1(x) in for y.
f^-1(x) = 2x - 8
f^-1(4) = 2(4) - 8
f^-1(4) = 0
The answer is 13. The work is below
Answer: 5.5km
Step-by-step explanation:
The scale given 1 : 25 000 , and it was said that on the map , the distance between two railway stations is 22 cm , this means that the scale of the map is 1: 25000 cm.
The scale 1 : 25 000 means that each centimeters on the map represent 25 ,000 in real life ,therefore , to calculate the real distance between the two railway station , we have
25,000 X 22
= 550000 cm
To convert this to km
Recall that
1 km = 100,000 cm
Therefore we will divide the answer by 100,000 , that is
550000/100000
= 5.5 km
Therefore , the real distance between the two railway stations is 5.5km
Answer:
$54.37
Step-by-step explanation:
First, need to find 15% of 47.28.
47.28 x .15 = 7.092
Then we add that to the original cost.
47.28+7.092 = 54.372
Round your answer
$54.37
Hope this helped!
