cot(<em>θ</em>) = cos(<em>θ</em>)/sin(<em>θ</em>)
So if both cot(<em>θ</em>) and cos(<em>θ</em>) are negative, that means sin(<em>θ</em>) must be positive.
Recall that
cot²(<em>θ</em>) + 1 = csc²(<em>θ</em>) = 1/sin²(<em>θ</em>)
so that
sin²(<em>θ</em>) = 1/(cot²(<em>θ</em>) + 1)
sin(<em>θ</em>) = 1 / √(cot²(<em>θ</em>) + 1)
Plug in cot(<em>θ</em>) = -2 and solve for sin(<em>θ</em>) :
sin(<em>θ</em>) = 1 / √((-2)² + 1)
sin(<em>θ</em>) = 1/√(5)
90 degrees
Acute tri
some trapezoids are paralellelograms
Answer:
Slope is undefined.
Step-by-step explanation:
Slope of 0 is a horizontal line.
Slope of undefined is a vertical line.
Any other slope is something in between.
Answer:
34
Step-by-step explanation:
so 56 -89 is 23
e3 - y7 divided by the quotient is 7
all u do is see what looked right and add
