10 images per day. Since it can receive 3 mb per second for 11 hours a day, that’s up to 118,800 megabits it can receive in one day. By multiplying the amount of gigabits in a typical picture (11.2) by the amount of megabits in a gigabit (1024) you get that there’s 11,468.8 megabits in each picture. Lastly, divide the number of megs that the station receives in one day by the amount of megs in a picture, and you get 10 and some change, therefore it can receive up to ten FULL pictures in a day
If he is 4 now is in 10 years he will be 14 and if you multiply that by 2 you get 28 which means in 10 years Marie will be 28 so that means if you take away 10 the answer should be 18 but that isn't there but that's how I would work it out.
Answer:
-50
Explanation:
Sum of 6 + sum of 4 = -100
100 + sum of 4 = -100
sum of 4 = -200
Avg of 4 = -200/4 = -50
Is this muliorple answer?