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Greeley [361]
2 years ago
12

Simplify the expression.

Mathematics
1 answer:
Anna71 [15]2 years ago
5 0

Since we have a cubic root, we're interested in factoring cubes inside the root, so that we can take them out. If we factor 648, we have

648=2^3\times 3^4=2^3\times 3^3\times 3 = (2\times 3)^3\times 3 = 3\times 6^3

So, we have

3x\sqrt[3]{648 x^4 y^8} = \sqrt[3]{3\times 6^3\cdot x^3\cdot x \cdot y^6\cdot y^2}=3x\cdot 6\cdot x\cdot y^2\sqrt[3]{3\cdot x\cdot y^2}

And the result simplifies to

18x^2y^2\sqrt[3]{3xy^2}

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Fill the value of the expression 24 3/5 +4 ×(8 1/5-2)
Julli [10]
First off, we'll convert the mixed fractions to "improper",

\bf \stackrel{mixed}{24\frac{3}{5}}\implies \cfrac{24\cdot 5+3}{5}\implies \stackrel{improper}{\cfrac{123}{5}}
\\\\\\
\stackrel{mixed}{8\frac{1}{5}}\implies \cfrac{8\cdot 5+1}{5}\implies \stackrel{improper}{\cfrac{41}{5}}

\bf 24\frac{3}{5}\times \left( 8\frac{1}{5}-2 \right)\implies \cfrac{123}{5}\left( \cfrac{41}{5}-2 \right)\impliedby \mathbb{PEMDAS}
\\\\\\
\cfrac{123}{5}\left( \cfrac{41-10}{5} \right)\implies \cfrac{123}{5}\left( \cfrac{31}{5} \right)
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\cfrac{123\cdot 31}{5\cdot 5}\implies \cfrac{3813}{25}\implies 152\frac{13}{25}
4 0
2 years ago
The set of ordered pairs represents a functuon. Write a rule represents the function. (0,0),(1,6),(2,24),(3,54),(4,96)
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notsponge [240]

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Answer:

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jekas [21]

keeping in mind that standard form for a linear equation means

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• only the constant on the right-hand-side

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\bf \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{3}}{3(y+5)=3\left( \cfrac{2}{3}(x+1) \right)}\implies 3y+15 = 2(x+1) \implies 3y+15=2x+2 \\\\\\ 3y=2x-13\implies -2x+3y=-13\implies 2x-3y=13

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