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3 years ago

find the scale, k, of H(3,4) if H'(9,12) after going through the transformation (x,y) ---> (kx,ky) centered at the origin

Mathematics

1 answer:

stiks02 [169]3 years ago

5 0

The value of scale k is 3

Step-by-step explanation:

In order to find the scale , we can either divide the coordinates of H' by the original point or compare both the points to find the original ordered pair.

Given

H(3,4)

H'(9,12)

The coordinates of H are multiplied with some integer k to form H'

So,

For x-coordinate:

3k = 9

k = 9/3 = 3

For y-coordinate:

4k = 12

k = 12/4 = 3

Hence,

The value of scale k is 3

Keywords: Coordinate geometry, scaling

Learn more about scaling at:

#LearnwithBrainly

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X-3y-7=0 , 3x-3y-15=0 solve this using cross multiplication

rewona [7]

Answer:

x = 4 , y = -1

Step-by-step explanation:

x - 3y = 7 -- (1)

3x - 3y = 15 -- (2)

Rewriting (1), x = 3y + 7 -- (1)'

Substituting (1)' into (2),

3 ( 3y + 7 ) - 3y = 15

9y + 21 - 3y = 15

6y = -6

y = -1 -- (3)

Substituting (3) into (1),

x - 3 ( - 1 ) = 7

x + 3 = 7

x = 4 -- (4)

According to (3) and (4),

x = 4 , y = -1

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2 years ago

Solve the following quadratic equation by the square root method. (Y-9)^2=64

enot [183]

Hello!

To solve this, first perform the opposite operation for the last operation (on the left side) on both sides. The last operation of the left side is squaring. Therefore, square root both sides.

$(y - 9)^{2} = 64$

$y - 9 = ±\sqrt{64}$

$y - 9 = ±8$

Please note that you must include ±. This is because the square root of 64 can be either positive or negative, as a square of either a positive or negative number is positive.

Now, add 9 to both sides.

$y = 9±8$