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Sedaia [141]
3 years ago
14

Lita jogged for 7*3/10 kilometers on Friday. She jogged 1*3/4 kilometres more on Saturday. How many kilometres did she jog on bo

th days?give your answer as a decimal.
Mathematics
1 answer:
Elza [17]3 years ago
8 0
7*3/10 = 2.1

1*3/4 = 0.75

2.1 + 0.75 = 2.85

hope this helps :)

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What is 6/51 written as a lowest term
daser333 [38]
2/17 is the lowest term for 6/51
7 0
3 years ago
Sailors traditionally measure speed in knots or nautical miles per hour . A nautical mile is based on the circumfrance of earth
sergejj [24]

Answer:

25.31 Feet per second

Step-by-step explanation:

7 0
3 years ago
What is the eighth term of the sequence below?
SpyIntel [72]

Answer:

A. 33

Step-by-step explanation:

Add 4 to each number

1. 5 is your first number

2. 5+4= 9 is your second number

3. 9+4= 13 is your third number

4. 13+4= 17 ...

5. 17+4= 21 ...

6. 21+4= 25 ...

7.25+4= 29 ...

8.29+ 4= 33 is your eight number

5 0
2 years ago
a student found the volume of a rectangular pyramid with a base area of 92 square meters and a height of 54 Meters to be 4968 cu
Naya [18.7K]
It is not correct. 

The student found the volume by multiplying the base area with the height. He forgot to divide it by 3.

Formula to find the volume of the pyramid = 1/3 base area x height

volume = 1/3 x 92 x 54 = 1656 square meters 
6 0
4 years ago
Read 2 more answers
Solve the following differential equations or initial value problems. In part (a), leave your answer in implicit form. For parts
shepuryov [24]

Answer:

(a) (y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) y = arctan(t(lnt - 1) + C)

(c) y = -1/ln|0.09(t + 1)²/t|

Step-by-step explanation:

(a) dy/dt = (t^2 + 7)/(y^4 - 4y^3)

Separate the variables

(y^4 - 4y^3)dy = (t^2 + 7)dt

Integrate both sides

(y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) dy/dt = (cos²y)lnt

Separate the variables

dy/cos²y = lnt dt

Integrate both sides

tany = t(lnt - 1) + C

y = arctan(t(lnt - 1) + C)

(c) (t² + t) dy/dt + y² = ty², y(1) = -1

(t² + t) dy/dt = ty² - y²

(t² + t) dy/dt = y²(t - 1)

(t² + t)/(t - 1)dy/dt = y²

Separating the variables

(t - 1)dt/(t² + t) = dy/y²

tdt/(t² + t) - dt/(t² + t) = dy/y²

dt/(t + 1) - dt/(t(t + 1)) = dy/y²

dt/(t + 1) - dt/t + dt/(t + 1) = dy/y²

Integrate both sides

ln(t + 1) - lnt + ln(t + 1) + lnC = -1/y

2ln(t + 1) - lnt + lnC = -1/y

ln|C(t + 1)²/t| = -1/y

y = -1/ln|C(t + 1)²/t|

Apply y(1) = -1

-1 = ln|C(1 + 1)²/1|

-1 = ln(4C)

4C = e^(-1)

C = (1/4)e^(-1) ≈ 0.09

y = -1/ln|0.09(t + 1)²/t|

8 0
4 years ago
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