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Ilia_Sergeevich [38]
3 years ago
6

For the​ following, indicate whether a confidence interval for a proportion or mean should be constructed to estimate the variab

le of interest. Justify your response. Does chewing your food for a longer period of time reduce​ one's caloric intake of food at​ dinner? A researcher requires a sample of 75 healthy males to chew their food twice as long as they normally do. The researcher then records the calorie consumption at dinner.
Mathematics
2 answers:
Black_prince [1.1K]3 years ago
6 0

Answer:

A confidence interval for a mean

Step-by-step explanation:

anzhelika [568]3 years ago
4 0

Answer:

A confidence interval for a mean should be constructed to estimate the variable of interest.

Step-by-step explanation:

The confidence interval for a mean uses the sample mean to estimate the true population mean.  Since it is a confidence interval, instead of a single number for the mean, the result shows a lower estimate and an upper estimate of the mean.  In this experiment, the confidence interval cannot be for a proportion since the population of healthy males is unknown, but the calculation is being done with a sample of 75 healthy males.

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What is the measure of env (5x+57)degrees
SashulF [63]

Answer:

D) 132°

Step-by-step explanation:

8x+12=5x+57    subtract 5x from both sides

3x+12=57           subtract 12 from both sides

3x= 45                divide by 3 from both sides

X=15

5(15)+57=132°

6 0
3 years ago
(-2/3)^7*(3/5)^6*(5/6)^5*(1/3)^-7 simplify of law of indices ​
Wewaii [24]

Answer:

\boxed {-\frac{12}{5}}

Step-by-step explanation:

Solve the following expression:

(-\frac{2}{3})^{7} \times (\frac{3}{5})^{6} \times (\frac{5}{6})^{5} \times (\frac{1}{3})^{-7}

-Calculate -\frac{2}{3} to the power of 7:

(-\frac{2}{3})^{7} \times (\frac{3}{5})^{6} \times (\frac{5}{6})^{5} \times (\frac{1}{3})^{-7}

-\frac{128}{2187} \times (\frac{3}{5})^{6} \times (\frac{5}{6})^{5} \times (\frac{1}{3})^{-7}

-Calculate \frac{3}{5} to the power of 6:

-\frac{128}{2187} \times (\frac{3}{5})^{6} \times (\frac{5}{6})^{5} \times (\frac{1}{3})^{-7}

-\frac{128}{2187} \times (\frac{729}{15625}) \times (\frac{5}{6})^{5} \times (\frac{1}{3})^{-7}

-Multiply both -\frac{128}{2187} and \frac{729}{15625}:

-\frac{128}{2187} \times (\frac{729}{15625}) \times (\frac{5}{6})^{5} \times (\frac{1}{3})^{-7}

-\frac{128}{46875} \times (\frac{5}{6})^{5} \times (\frac{1}{3})^{-7}

-Calculate \frac{5}{6} to the power of 5:

-\frac{128}{46875} \times (\frac{5}{6})^{5} \times (\frac{1}{3})^{-7}

-\frac{128}{46875} \times (\frac{3125}{7776}) \times (\frac{1}{3})^{-7}

-Multiply both -\frac{128}{46875} and \frac{3125}{7776}:

-\frac{128}{46875} \times (\frac{3125}{7776}) \times (\frac{1}{3})^{-7}

-\frac{4}{3645} \times (\frac{1}{3})^{-7}

-Calculate \frac{1}{3} to the power of -7:

-\frac{4}{3645} \times (\frac{1}{3})^{-7}

-\frac{4}{3645} \times 2181

-Multiply both the -\frac{4}{3645} and 2187:

-\frac{4}{3645} \times 2181

\boxed {-\frac{12}{5}}

Therefore, the final answer is -\frac{12}{5}.

3 0
3 years ago
Hey besties help me
forsale [732]

2x + 6 = 4x/2 + 12/2

To solve this, we need to transpose like terms to the same side.

2x - 4x/2 = 12/2 - 6

2x - 2x = 6 - 6

0 = 0

Since both sides are zero, it means that the equation has infinite number of solutions.

7 0
2 years ago
Read 2 more answers
A bag contains three red marbles, two green ones, one lavender one, four yellows, and five orange marbles. HINT [See Example 7.
kirill115 [55]

Answer:

There are 12 sets of four marbles include all the red ones.    

Step-by-step explanation:

Given : A bag contains three red marbles, two green ones, one lavender one, four yellows, and five orange marbles.

To find : How many sets of four marbles include all the red ones?

Solution :

Number of red marbles = 3

Number of green marbles = 2

Number of lavender marbles = 1

Number of yellow marbles = 4

Number of orange marbles = 5

We have to form sets of four marbles include all the red ones,

For position of getting red ones we have three red marbles i.e. ^3C_3

For the fourth one we have 12 choices i.e. ^{12}C_1

Total sets of four marbles include all the red ones is

=^3C_3\times ^{12}C_1

=1\times 12

=12

Therefore, There are 12 sets of four marbles include all the red ones.

5 0
2 years ago
Four people each deliver food to peoples' homes. Audrey charges a flat fee of $4 for each delivery plus a certain amount, in dol
timama [110]

Answer:

4+1m??

Step-by-step explanation:

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3 years ago
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