I don't know how many paragraphs your professor needs you to develop, but if your essay consists on just 3 paragraphs (introduction, body and conclusion) your thesis is OK.
Now, if your essay needs to have, lets say 4 or 5 paragraphs (introduction, body 1, body 2, body 3, and conclusion) I'd recommend you to add two more details to your essay. For example,
Schizophrenia is a severe mental illness that deeply affects not only the patient's daily life, but also his family and friends.
paragraph 1 is to develop how schizophrenia affects the patient daily life only. Paragraph 2 is to develop how schizophrenia affects the patient's family and paragraph 3 to develop how it affects his or her family.
Don't forget to put examples, professors love when you put examples.
Good luck, and if you need help, you can ask me.
Answer:
pls mark brainy
Step-by-step explanation:
option (d) is correct.
An equivalent form of the given compound inequality −44 > −2x − 8 ≥ −8 is −44 > −2x − 8 and −2x − 8 ≥ −8
Step-by-step explanation:
Given a compound inequality −44 > −2x − 8 ≥ −8
We have to write an equivalent form of compound inequality.
Compound inequality consists of two inequalities joined together and the solution is the intersection of each inequality.
Compound inequality has two sides the left hand side and right hand side we can solve them by taking each inequality one at a time.
For given compound inequality, −44 > −2x − 8 ≥ −8
we have
Left side of inequality as −44 > −2x − 8
and right side of inequality as −2x − 8 ≥ −8
Thus, option (d) is correct.
Thus, An equivalent form of the given compound inequality −44 > −2x − 8 ≥ −8 is −44 > −2x − 8 and −2x − 8 ≥ −8
Answer:
z= 3.63
z for significance level = 0.05 is ± 1.645
Step-by-step explanation:
Here p = 42% = 0.42
n= 500
We formulate our null and alternative hypotheses as
H0: p= 0.42 against Ha : p> 0.42 One tailed test
From this we can find q which is equal to 1-p= 1-0.42 = 0.58
Taking p`= 0.5
Now using the z test
z= p`- p/ √p(1-p)/n
Putting the values
z= 0.5- 0.42/ √0.42*0.58/500
z= 0.5- 0.42/ 0.0220
z= 3.63
For one tailed test the value of z for significance level = 0.05 is ± 1.645
Since the calculated value does not fall in the critical region we reject our null hypothesis and accept the alternative hypothesis that more than 42% people owned cats.
Time taken to drive to her grandparents house = 6 5/6 hours
We convert this mixed into improper fraction, we get = 41/6 hours
Time taken to drive to her grandparents house = 41/6 hours
Time taken to drive back = 8 2/9 hours
We convert this mixed into improper fraction, we get = 74/9 hours
Time taken to drive back = 74/9 hours
Difference between the two = 74/9 - 41/6 = (148-123)/18 = 25/18 hours = 1 7/18 hours
Therefore it took 1 7/18 hours longer to drive back.
I believe it is 64 miles.
Hope this helps! :)
