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4 years ago

Write a simple question requiring Pi. (No multiple choice)

Mathematics

2 answers:

Vesnalui [34]4 years ago

6 0

The area of a circle is 154m² find the radius in (dam)
Hint:1dam=0.1m

PilotLPTM [1.2K]4 years ago

5 0

The radius of a circle is 5cm. what is the circumference?

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The number of potato chips in a bag is normally distributed with a mean of 74 and and a standard deviation of 4. Approximately w

aleksklad [387]

Answer:

99.8% is the percent of bags contain between 62 and 86 potato chips.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 74

Standard Deviation, σ = 4

We are given that the distribution of number of potato chips in a bag is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

P( bags contain between 62 and 86 potato chips)

$P(62 \leq x \leq 86) = P(\displaystyle\frac{62 - 74}{4} \leq z \leq \displaystyle\frac{86-74}{4}) = P(-3 \leq z \leq 3)\\\\= P(z \leq 3) - P(z < -3)\\= 0.999 - 0.001 = 0.998 = 99.8\%$

$P(62 \leq x \leq 86) = 99.8\%$

7 0

3 years ago

Read 2 more answers

Express each ratio as a unit rate. 325.4 miles on 17.3 gallons having trouble :/

kkurt [141]

Hello! I can help you with this question! To find the unit rate, we’ll have to divide total by number of units. Or in this case, miles/gallons. 325.4/17.3 is 18.809 and other numbers, or 18.81 when rounded to the nearest hundredth. If you’re looking for the answer to the nearest hundredth, the answer is 18.81 mpg. Or, if you’re looking for the answer to the nearest whole number, the answer is 19 mpg.

8 0

3 years ago

You have to work on Distributive property 14(5+4)

lukranit [14]

126

explanation: solved it

3 0

3 years ago

Find the area of a circle with a diameter of 14 meters. Round your answer to the nearest hundredth of a square meter.

Jlenok [28]

To find the area of the circle:

⇒ need to know the formula: $\pi r^{2}$

r: radius or half of diameter's length ⇒ 7 meters

Let's calculate:

$Area = \pi (7)^2=49\pi =153.9380m^3$

The problem asks us to round to the nearest hundreth:

$Area = 153.94m^3$

Answer: $153.94m^3$

Hope that helps!

4 0

2 years ago

Use technology or a z-score table to answer the question.

Alik [6]

Answer:

The second choice: Approximately $65.2\%$ of the pretzel bags here will contain between 225 and 245 pretzels.

Step-by-step explanation:

This explanation uses a z-score table where each $z$ entry has two decimal places.

Let $\mu$ represent the mean of a normal distribution of variable $X$ . Let $\sigma$ be the standard deviation of the distribution. The z-score for the observation $x$ would be:

$\displaystyle z = \frac{x - \mu}{\sigma}$ .

In this question,

$\mu = 240$ .
$\sigma = 9.3$ .

Calculate the z-score for $x_1 = 225$ and $x_2 = 245$ . Keep in mind that each entry in the z-score table here has two decimal places. Hence, round the results below so that each contains at least two decimal places.

$\begin{aligned} z_1 &= \frac{x_1 - \mu}{\sigma} \\ &= \frac{225 - 240}{9.3} \approx -1.61\end{aligned}$ .

$\begin{aligned} z_2 &= \frac{x_2 - \mu}{\sigma} \\ &= \frac{245 - 240}{9.3} \approx 0.54\end{aligned}$ .

The question is asking for the probability $P(225 \le X \le 245)$ (where $X$ is between two values.) In this case, that's the same as $P(-1.61 \le Z \le 0.54)$ .

Keep in mind that the probabilities on many z-table correspond to probability of $P(Z \le z)$ (where $Z$ is no greater than one value.) Therefore, apply the identity $P(z_1 \le Z \le z_2) = P(Z \le z_2) - P(Z \le z_1)$ to rewrite $P(-1.61 \le Z \le 0.54)$ as the difference between two probabilities:

$P(-1.61 \le Z \le 0.54) = P(Z \le 0.54) - P(Z \le -1.61)$ .

Look up the z-table for $P(Z \le 0.54)$ and $P(Z \le -1.61)$ :

$P(Z \le 0.54)\approx 0.70540$ .
$P(Z \le -1.61) \approx 0.05370$ .

$\begin{aligned}& P(225 \le X \le 245) \\ &= P\left(\frac{225 - 240}{9.3} \le Z \le \frac{245 - 240}{9.3}\right)\\&\approx P(-1.61 \le Z \le 0.54) \\ &= P(Z \le 0.54) - P(Z \le -1.61)\\ &\approx 0.70540 - 0.05370 \\& \approx 0.65.2 \\ &= 65.2\% \end{aligned}$ .

3 0

4 years ago