The first five terms of the sequence are 1, 4, 7, 10, 13.
Solution:
Given data:
General term of the arithmetic sequence.
, where d is the common difference.
d = 3
Put n = 2 in , we get
Put n = 3 in , we get
Put n = 4 in , we get
Put n = 5 in , we get
The first five terms of the sequence are 1, 4, 7, 10, 13.
Answer: the tuition in 2020 is $502300
Step-by-step explanation:
The annual tuition at a specific college was $20,500 in 2000, and $45,4120 in 2018. Let us assume that the rate of increase is linear. Therefore, the fees in increasing in an arithmetic progression.
The formula for determining the nth term of an arithmetic sequence is expressed as
Tn = a + (n - 1)d
Where
a represents the first term of the sequence.
d represents the common difference.
n represents the number of terms in the sequence.
From the information given,
a = $20500
The fee in 2018 is the 19th term of the sequence. Therefore,
T19 = $45,4120
n = 19
Therefore,
454120 = 20500 + (19 - 1) d
454120 - 20500 = 19d
18d = 433620
d = 24090
Therefore, an
equation that can be used to find the tuition y for x years after 2000 is
y = 20500 + 24090(x - 1)
Therefore, at 2020,
n = 21
y = 20500 + 24090(21 - 1)
y = 20500 + 481800
y = $502300
1 4 . 8 3333
6 8 9 50
14.8333
ABC
MIT
MEL
are right triangles
to solve this you can get help from
ThePythagorean Proposition
or use an useful app all in one calculator
