Lets write an equation for each guy's shots and score:
4A + 2B = 18
3A + 3B = 21
To solve we multiply the first equation by -3 and the second by 2:
-12A - 6B = -54
6A + 6B = 42
--------------------
-12A + 0 = -12
A = 1
to find B we substitute in the first equation:
<span>4A + 2B = 18
</span><span>4(1) + 2B = 18
</span><span>4 + 2B = 18
</span>2B = 14
B = 7
therefore there were given 7 points in an arrow in B
Answer:
does NOT have right angles at the corners
Step-by-step explanation:
we are given that the sides of a table are 27" and 36" long.
If we assume the table to be rectangular, then by Pythagorean formula, we can find the diagonal and compare it to the 40" that we are given.
(refer to attached)
diagonal² = 27² + 36²
diagonal² = 27² + 36²
diagonal² = 2025
diagonal = √2025
diagonal = 45 inches
because the diagonal that we found is not the same as the 40" that was given, we can conclude that the table is not a rectangle (i.e does not have right angles at the corners)
773.77*0.5=386.88 hope i helped
Answer: 0.1457
Step-by-step explanation:
Let p be the population proportion.
Given: The proportion of Americans who are afraid to fly is 0.10.
i.e. p= 0.10
Sample size : n= 1100
Sample proportion of Americans who are afraid to fly =
We assume that the population is normally distributed
Now, the probability that the sample proportion is more than 0.11:
![P(\hat{p}>0.11)=P(\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}>\dfrac{0.11-0.10}{\sqrt{\dfrac{0.10(0.90)}{1100}}})\\\\=P(z>\dfrac{0.01}{0.0090453})\ \ \ [\because z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}} ]\\\\=P(z>1.1055)\\\\=1-P(z\leq1.055)\\\\=1-0.8543=0.1457\ \ \ [\text{using z-table}]](https://tex.z-dn.net/?f=P%28%5Chat%7Bp%7D%3E0.11%29%3DP%28%5Cdfrac%7B%5Chat%7Bp%7D-p%7D%7B%5Csqrt%7B%5Cdfrac%7Bp%281-p%29%7D%7Bn%7D%7D%7D%3E%5Cdfrac%7B0.11-0.10%7D%7B%5Csqrt%7B%5Cdfrac%7B0.10%280.90%29%7D%7B1100%7D%7D%7D%29%5C%5C%5C%5C%3DP%28z%3E%5Cdfrac%7B0.01%7D%7B0.0090453%7D%29%5C%20%5C%20%5C%20%5B%5Cbecause%20z%3D%5Cdfrac%7B%5Chat%7Bp%7D-p%7D%7B%5Csqrt%7B%5Cdfrac%7Bp%281-p%29%7D%7Bn%7D%7D%7D%20%5D%5C%5C%5C%5C%3DP%28z%3E1.1055%29%5C%5C%5C%5C%3D1-P%28z%5Cleq1.055%29%5C%5C%5C%5C%3D1-0.8543%3D0.1457%5C%20%5C%20%5C%20%5B%5Ctext%7Busing%20z-table%7D%5D)
Hence, the probability that the sample proportion is more than 0.11 = 0.1457
All I can say is 1 and 2 are correct.