Please answer the question below and show working
1 answer:
Answer:
i. Slope=-1/6
ii. Midpoint= (1,8.5)
iii. <em>Distance</em><em>=</em><em> </em><em>√</em><em>3</em><em>7</em><em> </em><em>units</em>
<em>iv.</em><em> </em><em> </em><em> </em><em> </em><em>Slope </em><em>of </em><em>t=</em><em>2</em>
<em>please </em><em>see</em><em> the</em><em> attached</em><em> picture</em><em> for</em><em> full</em><em> solution</em><em>.</em><em>.</em><em>.</em>
<em>Hope </em><em>it</em><em> helps</em><em>.</em><em>.</em>
<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em><em>.</em>
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Answer: 32°
Step-by-step explanation: see photo
Answer:
x = 150°
Step-by-step explanation:
The given parameters are;
AB ║ DC
∠BAE = 105°
∠AEC = 25°
We construct a line CF from C parallel to the line AE as presented in the included diagram created with Microsoft Visio
We have;
∠DCF ≅ ∠BAE = 105° by similar angles formed by two pairs of parallel lines
∠AEC = ∠ECF = 25° by alternate interior angles formed by two parallel lines and a common transversal
x = 125° + 25° = 150° By angle addition postulate
x = 150°.
