1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
alexandr1967 [171]
3 years ago
12

PLZ HELP!

Mathematics
2 answers:
puteri [66]3 years ago
7 0

Answer:

42 square units is not correct because you have to find the area of the rectangle(QUTR) and the area of the triangle(RST)

Area of rectangle is 42 square units

Area of the triangle is 10.5 square units

Add both which gives you the area of the polygon QRSU - 52.5 Square units  

Point Q is 6 units from Point R.

Point R is 7 units from Point T.

Point T is 3 units from Point S.

The area of polygon QRSU is 52.5 square units.

Step-by-step explanation:


brilliants [131]3 years ago
6 0
Point Q is 6 units from Point R.
Point R is 7 units from Point T.
Point T is 3 units from Point S.
The area of polygon QRSU is 42 square units.
Please mark my answer brainliest so I can move up to the next rank.
You might be interested in
The _______ form of a quadratic equation is written y = a(x - h)2 + k.
uranmaximum [27]

its wrong

Step-by-step explanation:

5 0
3 years ago
2x + 3x + 4 equals .
RUDIKE [14]
Add like terms
only add x's together
2x+3x=5x

we can't add x's and numbres so
answer is 5x+4
7 0
3 years ago
The total arm and blade of a windshield wiper is 12 in. long and rotates back and forth through an angle of 85°. The shaded regi
valkas [14]

Answer:

e

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
What does Evaluate each expression mean?
Sedbober [7]
The answer is to solve each expression.
3 0
3 years ago
Read 2 more answers
Use the following matrices, A, B, C and D to perform each operation.
Vinvika [58]

Step-by-step explanation:

A=\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]

B=\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]

C=\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]

D=\left[\begin{array}{ccc}-2&3&4\\0&-2&1\\3&4&-1\end{array}\right]

1.\\A+B=\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]+\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]=\left[\begin{array}{ccc}3+4&1+1\\5+6&7+0\end{array}\right]=\left[\begin{array}{ccc}7&2\\11&7\end{array}\right]

2.\\B-A=\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]-\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]=\left[\begin{array}{ccc}4-3&1-1\\6-5&0-7\end{array}\right]=\left[\begin{array}{ccc}1&0\\1&-7\end{array}\right]

3.\\3C=3\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]=\left[\begin{array}{ccc}(3)(-2)&(3)(3)&(3)(1)\\(3)(-1)&(3)(0)&(3)(4)\end{array}\right]=\left[\begin{array}{ccc}-6&9&3\\-3&0&12\end{array}\right]

4.\\C\cdot D=\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]\cdot\left[\begin{array}{ccc}-2&3&4\\0&-2&1\\3&4&-1\end{array}\right]\\\\=\left[\begin{array}{ccc}(-2)(-2)+(3)(0)+(1)(3)&(-2)(3)+(3)(-2)+(1)(4)&(-2)(4)+(3)(1)+(1)(-1)\\(-1)(-2)+(0)(0)+(4)(3)&(-1)(3)+(0)(-2)+(4)(4)&(-1)(4)+(0)(1)+(4)(-1)\end{array}\right]\\=\left[\begin{array}{ccc}7&-8&-6\\14&13&-8\end{array}\right]

5.\\2D+3C\\\text{This operation can't be performed because the matrices}\\\text{ are of different dimensions.}

6 0
3 years ago
Other questions:
  • What is the inverse of the function f(x) = 4x + 8 a. h(x) 1/4 x - 2
    7·1 answer
  • Which is greater 10 yards or 360 inches?
    15·1 answer
  • What is the volume of this?
    9·2 answers
  • Somebody please help me
    14·1 answer
  • PLZ HELP!! I NEED ASAP
    6·1 answer
  • Please help what does x=?
    8·2 answers
  • Ernesto has $70 in a savings account. The interest rate is 5%, compounded annually. To the nearest cent, how much will he have i
    15·1 answer
  • PLEASE HELP
    6·2 answers
  • Four times the sum of three consecutive integers is 180. What are the three integers?
    14·1 answer
  • Half of the sum of six and three then divided by 7
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!