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ch4aika [34]
3 years ago
10

Hund’s rule of maximum multiplicity specifies that _____. A. electrons will fill orbitals of lower energy first, pairing up only

after each orbital of the same energy already has one electron B. electrons will fill orbitals of lower energy first, pairing up only after each s and p orbital has one electron C. electrons will fill all of the s orbitals before filling any p orbitals D. the pattern by which electrons occupy orbitals cannot be predicted
Mathematics
1 answer:
djverab [1.8K]3 years ago
4 0

Answer:

A. electrons will fill orbitals of lower energy first, paring up only after each orbital of the same energy already has one electron

Step-by-step explanation:

The rule states that for a given electron configuration, the lowest energy term is the one with the greatest value of spin multiplicity. This implies that if two or more orbitals of equal energy are available, electrons will occupy them singly before filling them in pairs.

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Plz can you just answer c
Rasek [7]

Answer:

c. The mean is the same as the average. The average is (6 * 5 + 7 * 4 + 8 * 7 + 9 * 10 + 10 * 4) / (5 + 4 + 7 + 10 + 4) = 244 / 30 = 8.133.

5 0
3 years ago
What is the slope of the line through (-9,6)(−6),9)
lara31 [8.8K]

Answer:

1

Step-by-step explanation:

Well slope intercept is y2-y1 over x2-x1

So,

-6-(-9) over 9-6

3 over 3 which is 1

Your slope is 1

6 0
3 years ago
Read 2 more answers
Jada has 126 blue marbles and 135 yellow marbles. She packages them in bags of 8 marbles each. She divides the total number of m
FrozenT [24]

Answer:

Jada has 5 marbles left after filling 32 bags.

Step-by-step explanation:

Jada has 126 blue marbles and 135 yellow marbles

Total Marbles=126+135=261

She divides by 8: 261/8=32\frac{5}{8} i.e. 32 Remainder 5 marbles.

The correct interpretation is Jada has 5 marbles left after filling 32 bags.

3 0
3 years ago
A manufacturing company has two retail outlets. It is known that 30% of all potential customers buy
aleksandrvk [35]

Answer:

(a) A y P(A) = 0.4 (b) \bar{B} y P(\bar{B})=0.5 (c) \bar{A}∪\bar{B} y P(\bar{A}∪\bar{B}) = 0.9 (d) \bar{A}∩\bar{B} y P(\bar{A}∩\bar{B})=0.2

Step-by-step explanation:

A was defined as the event that a potential customer, randomly chosen, buys from outlet 1 in the original problem statement. We know that B denotes the event that a randomly chosen customer buys from outlet 2. So

P(A\cap \bar{B}) = 0.3, P(B\cap \bar{A}) = 0.4 and P(A\cap B) = 0.1

(a) P(A) = P(A\cap (B\cup\bar{B})) = P(A\cap B) + P(A\cap \bar{B}) = 0.1 + 0.3 = 0.4

(b)  P(B) = P(B\cap (A\cup\bar{A})) = P(B\cap A) + P(B\cap \bar{A}) = 0.1 + 0.4 = 0.5

P( \bar{B}) = 1-P(B) = 1-0.5 = 0.5

(c) The customer does not buy from outlet 1 is the complement of A, i.e.,  \bar{A}, and the customer does not buy from outlet 2 is the complement of B, i.e.,  \bar{B}, so, the customer does not buy from outlet 1 or does not buy from outlet 2 is  \bar{A}∪ \bar{B} and P(\bar{A}∪ \bar{B}) = P((A\cap B)^{c}) by De Morgan's laws

P((A\cap B)^{c})  = 1-P(A∩B)=1-0.1=0.9

(d) The customer does not buy from outlet 1 is the complement of A, and the customer does not buy from outlet 2 is the complement of B, so we have that the statement in (d) is equivalent to \bar{A}∩\bar{B} and P( \bar{A}∩\bar{B}) = P((AUB)^{c}) by De Morgan's laws, and

P((AUB)^{c}) = 1-P(A∪B)=1-[P(A)+P(B)-P(A∩B)]=1-[0.4+0.5-0.1]=1-0.8=0.2

8 0
3 years ago
Which of the following is another way to show the ratio 13 to 27
Semenov [28]
13:27 13/27 That's How You Show The Ratio
4 0
3 years ago
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