Given that,
ABC is a right angle triangle, C is the right angle.
To find,
cosB = ?
Solution,
The sum of angle of a triangle is equal to 180 degrees. So,
∠A + ∠B + ∠C = 180°
Put ∠C = 90°
∠A + ∠B + 90° = 180°
∠A + ∠B = 90°
Taking cos with each term.
cosA+cosB = cos (90)
cosA+cosB = 0
cosB=-sinA
Hence, cosB = sinA.
Answer:
it 66
Step-by-step explanation:
Since 3 is greater than -3, hence (-1, 3) lie in the solution set. Option C is correct
In order to determine the points that lie in the solution set of the inequality y > 3x +10, we will substitute the x-coordinate and see if <u>y is greater than the result.</u>
<u />
For the coordinate point (1, 10)
y > 3(1) +10
y > 13
Since 10 is not greater than 13, hence (1,10) does not lie in the solution set.
For the coordinate point (4, 20)
y > 3(4) +10
y > 22
Since 20 is not greater than 22, hence (4,20) does not lie in the solution set.
For the coordinate point (-1, 3)
y > 3(-1) +10
y > -7
Since 3 is greater than -3, hence (-1, 3) lie in the solution set.
Learn more on inequality here: brainly.com/question/24372553
Answer:
Step-by-step explanation:
* You must make sure that you have seven zeros in your decimal.
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The equation of a line of the slope-intersection form is given by:
Where:
m: It's the slope
b: It is the cut-off point with the y axis
If two lines are parallel then their slopes are equal.
We have the following line:
Thus, the slope of the line is -5.
Therefore a parallel line is of the form:
We replace the point 
Finally, the equation is of the form:
Answer:
