Answer:
a. 19x-13 b. 
Step-by-step explanation:
a. 3(-3+5x)-1(4-4x) = -9+15x-4+4x = 15x+4x-9-4 = 19x-13.
b. 
= 
Answer:
Um.... Wouldn't angle 1 just be 180-17 which is 163. Angle 3 would be equal to angle 1 so also 163. Angle 4 and angle 2 are equal to 17.
Step-by-step explanation:
Answer: 20
Step-by-step explanation:
I suppose the figure that you do not include in your exercise is the one that I attached.
Looking at the figure, it is obvious that the angle COA is divided into two angles of 20 degrees each, so the answer would be 20.

get rid of -2 by subtracting it from 21

Now you get your answer

Hope this helps! :)