Multiply 10.5 and 23.5 to get 246.75. Divide that by 3 and you have your answer, 82.25.
Answer:
The algebraic expression you are looking for is:
x^2*9
Answer:
Step-by-step explanation:
We want to determine a 95% confidence interval for the mean salary of all graduates from the English department.
Number of sample, n = 400
Mean, u = $25,000
Standard deviation, s = $2,500
For a confidence level of 95%, the corresponding z value is 1.96. This is determined from the normal distribution table.
We will apply the formula
Confidence interval
= mean ± z × standard deviation/√n
It becomes
25000 ± 1.96 × 2500/√400
= 25000 ± 1.96 × 125
= 25000 ± 245
The lower end of the confidence interval is 25000 - 245 =24755
The upper end of the confidence interval is 25000 + 245 = 25245
Therefore, with 95% confidence interval, the mean salary of all graduates from the English department is between $24755 and $25245
Answer:
M =6
Step-by-step explanation:
T2/T1=T3/T2
M/4=9/m
M^2=36
M=+ or - 6
As m is continued ignore - 6
Then get m =6
Answer:
5 1/8 pizza
Step-by-step explanation:
3/4=6/8
1/2=4/8
7/8=7/8
3
6/8+4/8+7/8=17/8= 2 1/8 pizza
3+2 1/8= 5 1/8
