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ValentinkaMS [17]
3 years ago
10

1. Write an algebraic expression for nine times of the square of a number.

Mathematics
1 answer:
Andreas93 [3]3 years ago
7 0

Answer:

The algebraic expression you are looking for is:

x^2*9

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The following data show the number of cars passing through a toll booth during a certain time period over 15 days. 18 19 17 17 2
IgorLugansk [536]

Answer: <em>third from the top</em>

Step-by-step explanation:

<em>The correct answer is third from the top.</em>

<em>Arranging numbers in ascending order: </em>

<em>15 17 17 17 18 18 18 19 19 19 21 21 22 23 24</em>

<em>Let's count how many times each number occurs in this series of numbers.</em>

<em>row of numbers</em>

<em>15 </em>+

<em>16 not</em>

<em>17 </em>+ + +

<em>18 </em>+ + +

<em>19 </em>+ + +

<em>20 not</em>

<em>21 </em>+ +

<em>22 </em>+

<em>23 </em>+

<em>24 </em>+

<em>25 not</em>

6 0
3 years ago
Please help with this question I will give points and brainliest thank you!
kramer

Answer:

that would be the middle ages

Step-by-step explanation:

6 0
3 years ago
The _____ a0 of a segment divides the segment into two segments of equal length.
Alexeev081 [22]

The <u>Midpoint</u> of a segment divides the segment into two segments of equal length.

6 0
3 years ago
Read 2 more answers
A probability experiment consists of rolling a fair 12​-sided die. Find the probability of the event below. rolling a 5
VladimirAG [237]
It is one out of twelve, if the twelve sides have all numbers from 1-12

6 0
4 years ago
Given: ABCD trapezoid, BK ⊥ AD , AB=DC AB=8, AK=4 Find: m∠A, m∠B
Elis [28]

Answer:

m\angle B=m\angle C=120^{\circ}

m\angle A=m\angle D=60^{\circ}

Step-by-step explanation:

Trapezoid ABCD is isosceles trapezoid, because AB = CD (given). In isosceles trapezoid, angles adjacent to the bases are congruent, then

  • \angle A\cong \angle D;
  • \angle B\cong \angle C.

Since BK ⊥ AD, the triangle ABK is right triangle. In this triangle,  AB = 8, AK = 4. Note that the hypotenuse AB is twice the leg AK:

AB=2AK.

If in the right triangle the hypotenuse is twice the leg, then the angle opposite to this leg is 30°, so,

m\angle ABK=30^{\circ}

Since BK ⊥ AD, then BK ⊥ BC and

m\angle KBC=90^{\circ}

Thus,

m\angle B=30^{\circ}+90^{\circ}=120^{\circ}\\ \\m\angle B=m\angle C=120^{\circ}

Now,

m\angle A=m\angle D=180^{\circ}-120^{\circ}=60^{\circ}

7 0
3 years ago
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