The length and width of the rug is 20 and 11 feet respectively
The given parameters;
dimension of the room = 19 ft by 28 ft
maximum area of rug she can afford = 220 ft²
For a uniform stripe of floor around the rug, then suppose the uniform excess length of the floor to removed from each dimension = y
(28-2x)(19-2x)=220
532-94x+4x^2=220
4x^2-94x+312=0
x=39/2,4
For x=39/2, dimensions are negative.
The uniform dimension of the floor to be covered by the maximum area of rug she can afford = (28 - 4×2) and (19 -2×4 ) = 20 and 11
Thus, the dimensions of the rug should be 20 feet and 11 feet
- The area of a rectangle is length times breadth.
- Area is the total squares cm occupied by a closed figure.
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Answer:
Step-by-step explanation:
this is the same equation, the system has infinitely many solutions
The answer is 56m^2.
The formula for finding area of a triangle is A=b•h/2.
So the base is 16m and the height is 7m. 16m•7m=112m^2
Now divide 112m^2 by 2.
112m^2/2=56m^2
You need to find common factors. The factors of 88 are 1 and 88, 2 and 44, 4 and 22, and 8 and 11. The factors of thirty are 1 and 30, 2 and 15, and 5 and 6. The greatest common factor is 2 so the ratio is 44:15.
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