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just olya [345]
2 years ago
8

Does anyone know the answers to this questions

Mathematics
1 answer:
steposvetlana [31]2 years ago
8 0

Answer:

6c + 36 =  6(c+6)

(6*c) + (6*6) =   6(c+6)

2(3c+3) =  6c+6

(6+c)+(6+6) =  neither

3c+6+3c =  6c+6

6c+12 =  neither

correct me if I am wrong cuz i haven't done this in 2 years

Step-by-step explanation:

going across the top row then the bottom

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Principle = 30,000<br>Time = 4 years<br>Rate = 30<br>Then find the simple interest ?​
Nutka1998 [239]

Answer:

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Given:}}}}}}\end{gathered}

  • {\dashrightarrow \sf{Principle = Rs.30000}}
  • {\dashrightarrow \sf {Time = 4 \: years}}
  • \dashrightarrow \sf{Rate = 30\%}
  • \begin{gathered}\end{gathered}

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{To Find:}}}}}}\end{gathered}

  • \dashrightarrow{\sf{Simple \: Interest }}

\begin{gathered}\end{gathered}

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Using Formula:}}}}}}\end{gathered}

\dag{\underline{\boxed{\sf{ S.I = \dfrac{P \times R \times T}{100}}}}}

Where

  • \dashrightarrow{\sf{S.I = Simple \:  Interest }}
  • {\dashrightarrow{\sf{P = Principle }}}
  • {\dashrightarrow{\sf{ R = Rate }}}
  • {\dashrightarrow{\sf{T = Time}}}

\begin{gathered}\end{gathered}

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Solution:}}}}}}\end{gathered}

{\quad {: \implies{\sf{ S.I =  \bf{\dfrac{P \times R \times T}{100}}}}}}

Substituting the values

{\quad {: \implies{\sf{ S.I =  \bf{\dfrac{30000 \times 30\times 4}{100}}}}}}

{\quad {: \implies{\sf{ S.I =  \bf{\dfrac{30000 \times 120}{100}}}}}}

{\quad {: \implies{\sf{ S.I =  \bf{\dfrac{3600000}{100}}}}}}

{\quad {: \implies{\sf{ S.I =  \bf{\cancel{\dfrac{3600000}{100}}}}}}}

{\quad {: \implies{\sf{ S.I =  \bf{Rs.36000}}}}}

{\dag{\underline{\boxed{\sf{ S.I ={Rs.36000}}}}}}

  • Henceforth,The Simple Interest is Rs.36000..

\begin{gathered}\end{gathered}

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Learn More:}}}}}}\end{gathered}

\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered} \dag \: \underline{\bf{More \: Useful \: Formula}}\\ {\boxed{\begin{array}{cc}\dashrightarrow {\sf{Amount = Principle + Interest}} \\ \\ \dashrightarrow \sf{ P=Amount - Interest }\\ \\ \dashrightarrow \sf{ S.I = \dfrac{P \times R \times T}{100}} \\ \\ \dashrightarrow \sf{P = \dfrac{Interest \times 100 }{Time \times Rate}} \\ \\ \dashrightarrow \sf{P = \dfrac{Amount\times 100 }{100 + (Time \times Rate)}} \\ \end{array}}}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}

8 0
2 years ago
Read 2 more answers
Find the distance between points A (5.-7) and B (-3,-4)
Strike441 [17]

It would help if you had a four quadrant graph, but the distance would be (8,11).

7 0
3 years ago
A box contains 4 oranges, 9 apples, and 3 pears. Liliana selects a piece of fruit from the box at random. What is the probabilit
valina [46]
Hello!

You first find out how many objects there are in total


4 + 9 + 3 = 16

Then you find the probability of Liliana picking a orange

Since there are 4 oranges and 16 things to pick she has a 4/16 chance of getting an orange

Next you find the probability of Liliana picking a pear

There are 3 pears and 16 items to pick so she has a 3/16 chance

Then you add them together to find the chance of either happening

4/16 + 3/16 = 7/16

So she has a 7 out of 16 chance of getting an orange or a pear

The answer is 7/16

Hope this helps!
3 0
3 years ago
2x+3y=12 find y and x intercepts
lord [1]

Answer:

Linear function 2x+3y=12 .

Step-by-step explanation:

To find y-intercept , make x=0 :

3y = 12

y = 12/3

y = 4 .

To find x-intercept , make y=0 :

2x = 12

x = 12/2

x = 6 .

<u> ! Hope this will help you !</u>

8 0
3 years ago
Hi, umm pls help<br><br> 1/6(x-5)=1/2(x+6), solve for x <br><br> And can you please explain
Mumz [18]

Answer:

By solving the equation \frac{1}{6}(x-5)=\frac{1}{2}(x+6) we found that   x=\frac{23}{2} \text { or }=11 \frac{1}{2}

<u>Explanation:  </u>

Given equation,

\frac{1}{6}(x-5)=\frac{1}{2}(x+6) to find x  

Step: 1 Cross multiply the denominators 2(x-5)=6(x+6)  

Step: 2 Open brackets and simplify the term 2x-10=6x+36  

Step: 3 Bring x terms on one side and simplify the equation the equation obtained is following,  

2x-6x=36+10

 -4x=46  

-x=\frac{46}{4}=\frac{23}{2}=11 \frac{1}{2}

Therefore, we solved x value from the given equation \frac{1}{6}(x-5)=\frac{1}{2}(x+6) as x=\frac{23}{2} \text { or }=11 \frac{1}{2}.

4 0
3 years ago
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