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olga_2 [115]
3 years ago
9

Determine which expressions are polynomials. Explain your reasoning.

Mathematics
1 answer:
Tom [10]3 years ago
8 0

Answer:

A, B

Step-by-step explanation:

A polynomial is an expression containing two or more algebraic terms. They are often the sum of several terms containing different powers (exponents) of variables and never contains square roots or division by a variable.

In your case, option A contains two terms that with second and first power of x. Therefore, the expression in A is a polynomial. Option B contains three  terms that with second, first power of x and coefficient. This is a polynomial too. Option C represents the absolute value of x and doesn't represent a polynomial.

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Help on this math question ‍♀️
noname [10]

Answer:

the 2nd 3rd and 4th answers are the correct ones

Step-by-step explanation:

hope this helps you

4 0
2 years ago
How much interest would you have if you deposited $200 that if you deposited $150? ​
Andrew [12]

Answer:

Difference = 206 - 154.5 = $51.5

In short, Your Answer would be: $51.5

7 0
2 years ago
Consider a particle moving along the x-axis where x(t) is the position of the particle at time t, x' (t) is its velocity, and x'
vodka [1.7K]

Answer:

a) v(t) =x'(t) = \frac{dx}{dt} = 3t^2 -12t +9

a(t) = x''(t) = v'(t) =6t-12

b)  0

c) a(t) = x''(t) = v'(t) =6t-12

When the acceleration is 0 we have:

6t-12=0, t =2

And if we replace t=2 in the velocity function we got:

v(t) = 3(2)^2 -12(2) +9=-3

Step-by-step explanation:

For this case we have defined the following function for the position of the particle:

x(t) = t^3 -6t^2 +9t -5 , 0\leq t\leq 10

Part a

From definition we know that the velocity is the first derivate of the position respect to time and the accelerations is the second derivate of the position respect the time so we have this:

v(t) =x'(t) = \frac{dx}{dt} = 3t^2 -12t +9

a(t) = x''(t) = v'(t) =6t-12

Part b

For this case we need to analyze the velocity function and where is increasing. The velocity function is given by:

v(t) = 3t^2 -12t +9

We can factorize this function as v(t)= 3 (t^2- 4t +3)=3(t-3)(t-1)

So from this we can see that we have two values where the function is equal to 0, t=3 and t=1, since our original interval is 0\leq t\leq 10 we need to analyze the following intervals:

0< t

For this case if we select two values let's say 0.25 and 0.5 we see that

v(0.25) =6.1875, v(0.5)=3.75

And we see that for a=0.5 >0.25=b we have that f(b)>f(a) so then the function is decreasing on this case.  

1

We have a minimum at t=2 since at this value w ehave the vertex of the parabola :

v_x =-\frac{b}{2a}= -\frac{-12}{2*3}= -2

And at t=-2 v(2) = -3 that represent the minimum for this function, we see that if we select two values let's say 1.5 and 1.75

v(1.75) =-2.8125< -2.25= v(1.5) so then the function sis decreasing on the interval 1<t<2

2

We see that the function would be increasing.

3

For this interval we will see that for any two points a,b with a>b we have f(a)>f(b) for example let's say a=3 and b =4

f(a=3) =0 , f(b=4) =9 , f(b)>f(a)

The particle is moving to the right then the velocity is positive so then the answer for this case is: 0

Part c

a(t) = x''(t) = v'(t) =6t-12

When the acceleration is 0 we have:

6t-12=0, t =2

And if we replace t=2 in the velocity function we got:

v(t) = 3(2)^2 -12(2) +9=-3

5 0
3 years ago
Nathan is organizing textbooks on his bookshelf. He has a Spanish textbook, a math
Ghella [55]

Answer:

6 ways

Step-by-step explanation:

Given:

Books: Spanish, Maths and History textbooks (1 each)

Required

Determine the number of arrangements

In total, Nathan has 3 books.

The number of arrangements (n) is as follows:

The first book can be lined in 3 ways

The second book can be lined in 2 ways

The third book can be lined in 1 way

So,

n = 3 * 2 * 1

n = 6

3 0
2 years ago
Read 2 more answers
Aarón rides his bike away from home at a constant speed he stops at the park for a while before riding back home at a constant s
Nikolay [14]

Answer:

Step-by-step explanation: This is the answer

5 0
2 years ago
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