All categories

3 years ago

Evaluate V= bh divided by 3 for B= 9 in 2 and h=32 in

Mathematics

1 answer:

Luba_88 [7]3 years ago

8 0

It would be 96 because V=(9)(32)= 288/3=96

You might be interested in

Please help question eleven

saw5 [17]

The answers D, the explanation is that it’s basically common sense just look for the same numbers and make it make sense :)

5 0

3 years ago

Solve 3[-x + (2 x + 1)] = X – 1. Х=

Strike441 [17]

Answer:

x=-2

Step-by-step explanation:

4 0

3 years ago

F(x)=2x-6 find f(2) please help

vladimir1956 [14]

Answer:

Step-by-step explanation:

Putting value of x = 2 in the equation

F(2) = 2(2) - 6

= 4 - 6

= - 2

7 0

2 years ago

In the figure to the right, AE + DC = 1 1/5 cm, AB = 1 3/4 cm, DE = 1 1/4 cm, and BC = 1 3/10 cm. Find the perimeter of the figu

nasty-shy [4]

Answer:

P= 5.5 cm

Step-by-step explanation:

The Perimeter of Plane Shapes

If we are given a plane shape, the perimeter is the measurement of the boundary of it. In case the shape is made of lines, the perimeter is the sum of the lengths of all of them.

We are given an irregular shape, we only need to add all the sides. But we don't have all the individual sides. Let's write the expression for the perimeter.

P=AE+ED+DC+CB+BA

We have: AE + DC = 1 1/5 cm, AB = 1 3/4 cm, DE = 1 1/4 cm, and BC = 1 3/10 cm. Note we don't have AE or DC, but we have their sum, so

P=AE+DC+ED+CB+BA

Recall that AB=BA, the order of the letters is not important. The perimeter is

$\displaystyle P=1\frac{1}{5}+1\frac{1}{4}+1\frac{3}{10}+1\frac{3}{4}$

We add the integer parts separate from the fractions

$\displaystyle P=4+\frac{1}{5}+\frac{1}{4}+\frac{3}{10}+\frac{3}{4}$

Now we use the common denominator (Least Common Multiple or LCM ) which is 20:

$\displaystyle P=4+\frac{4+5+6+15}{20}$

Operating

$\displaystyle P=4+\frac{30}{20}$

Simplifying

$\displaystyle P=4+\frac{3}{2}$

$\displaystyle P=\frac{11}{2}=5.5\ cm$

5 0

3 years ago

If α and β are the zeros of the quadratic polynomial f(x) = 6x²+x-2, then the value of

AVprozaik [17]

Answer:

Given function:

$f(x)=6x^2+x-2$

To find the zeros of the function, set the function to zero and factor:

$\implies 6x^2+x-2=0$

$\implies 6x^2+4x-3x-2=0$

$\implies 2x(3x+2)-1(3x+2)=0$

$\implies (2x-1)(3x+2)=0$

Therefore, the zeros are:

$\implies (2x-1)=0 \implies x=\dfrac{1}{2}$

$\implies (3x+2)=0 \implies x=-\dfrac{2}{3}$

If α and β are the zeros of the function:

$\textsf{Let } \alpha=\dfrac{1}{2}$

$\textsf{Let } \beta=-\dfrac{2}{3}$

Question 1

$\begin{aligned}\implies \alpha^2+\beta^2 & =\left(\dfrac{1}{2}\right)^2+\left(-\dfrac{2}{3}\right)^2\\\\& = \dfrac{1}{4}+\dfrac{4}{9}\\\\& = \dfrac{9}{36}+\dfrac{16}{36}\\\\& = \dfrac{25}{36}\end{aligned}$

Question 2

$\begin{aligned}\implies \dfrac{1}{\alpha}+\dfrac{1}{\beta} & = \dfrac{1}{\frac{1}{2}}+\dfrac{1}{-\frac{2}{3}}\\\\& = 1 \times \dfrac{2}{1}+1 \times -\dfrac{3}{2}\\\\& = 2 - \dfrac{3}{2}\\\\& = \dfrac{1}{2}\end{aligned}$

5 0

2 years ago

Read 2 more answers