<img src="https://tex.z-dn.net/?f=g%28x%29%3Dx%5E3%2B2x-1" id="TexFormula1" title="g(x)=x^3+2x-1" alt="g(x)=x^3+2x-1" align="abs

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alexira [117]

3 years ago

middle" class="latex-formula">.

Mathematics

1 answer:

Anastasy [175]3 years ago

5 0

First you differentiate it. So:
x^3 + 2x - 1 = 3x^2 + 2
at point (2, 1) the x value is 2 so you substitute that into the differentiated equation.
you get 3(2)^2 + 2 = 14

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