<img src="https://tex.z-dn.net/?f=g%28x%29%3Dx%5E3%2B2x-1" id="TexFormula1" title="g(x)=x^3+2x-1" alt="g(x)=x^3+2x-1" align="abs

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alexira [117]

3 years ago

middle" class="latex-formula">.

Mathematics

1 answer:

Anastasy [175]3 years ago

5 0

First you differentiate it. So:
x^3 + 2x - 1 = 3x^2 + 2
at point (2, 1) the x value is 2 so you substitute that into the differentiated equation.
you get 3(2)^2 + 2 = 14

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Write an equivalent expressions to 2x + 3 + 5x +6 by combining like terms Your standard form +

Stolb23 [73]

Answer:

7x+9

Step-by-step explanation:

combine like terms

plz brainliest!

8 0

3 years ago

6,666,666×666,666 /1+2+3+4+5+6+5+4+3+2+1 − 777,777×777,777/1+2+3+4+5+6+7+6+5+4+3+2+1

jeka57 [31]

Answer:

111111 $\times$ 1111110 is the simple expression.

Step-by-step explanation:

The expression to be solved:

$\dfrac{6,666,666\times666,666 }{1+2+3+4+5+6+5+4+3+2+1} - \dfrac{777,777\times777,777}{1+2+3+4+5+6+7+6+5+4+3+2+1}$

First of all, let us solve the first term:

$\dfrac{6,666,666\times666,666 }{1+2+3+4+5+6+5+4+3+2+1}\\\Rightarrow \dfrac{6666666\times666666 }{36}\\\Rightarrow \dfrac{6666666\times666666 }{6\times 6}\\\Rightarrow 1111111\times 111111$

Now, the right term:

$\dfrac{777777\times777777}{1+2+3+4+5+6+7+6+5+4+3+2+1}\\\Rightarrow \dfrac{777777\times777777}{49}\\\Rightarrow \dfrac{777777\times777777}{7 \times 7}\\\Rightarrow 111111 \times 111111$

So, the expression to be solved becomes:

$1111111\times 111111-111111\times 111111\\\Rightarrow 111111(1111111-1)\\\Rightarrow 111111\times 1111110$

3 0

3 years ago

Would each of them be able to be the side lengths of a triangle?

ratelena [41]

Pythagoras Theorem:
hipotenuse²=leg₁²+leg₂²

First posible triangle:
hypotenuse=13 (13²=169)
leg₁=12 ( 12²=144)
leg₂=5 (5²=25)

13³=144 + 25

Answer:can be side lengths of a triangle

Second triangle:
hypotenuse=12.6 (12.6²=158.76)
leg₁=6.7 ( 6.7²=44.89)
leg₂=6.5 (6.5²=42.25)

leg₁²+leg₂²=44.89+42.25=87.14≠158.76

Answer: cannot be side lenghts of a triangle.

third triangle:
hypotenuse=13 (13²=169)
leg₁=12 ( 12²=144)
leg₂=11 (11²=121)

leg₁²+leg₂²=144+121=265≠169

Answer: cannot be side lenghts of a triangle.

fourth triangle:
hypotenuse=13 (13²=169)
leg₁=6 ( 6²=36)
leg₂=4 (4²=16)

leg₁²+leg₁²=36+16=52≠169

Answer: cannot be side lenghts of a triangle.

8 0

3 years ago

Read 2 more answers

Solve for x. will mark brainliest

Veronika [31]

Answer: x=90

Step-by-step explanation: 11 x 7.5 =90

8 0

4 years ago

total of 420 tickets were sold for the school play. They were either adult tickets or student tickets. The number of student tic

Gnoma [55]

<span>2x + x = 420
3x = 420
x = 140 Adult tickets </span>

4 0

4 years ago