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3 years ago

How to find the asymtope of a function

1 answer:

3 0

Asymptote at x = 3 and a horizontal asymptote at y = 1. The curves approach these asymptotes but never cross them. The method used to find the horizontal asymptote changes depending on how the degrees of the polynomials in the numerator and denominator of the function compare.

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Let a and b be irrational numbers. Is a•b rational or irrational

SSSSS [86.1K]

Answer:

irrational

Step-by-step explanation:

when you multiply a irrational number by a rational number you dont lose the properties of an irrational number

6 0

3 years ago

V<br> Find the distance between the points (5, -3) and (5, 4).

Gwar [14]

Answer:

Distance = 7

Step-by-step explanation:

A(5 , -3) B(5,4)

D = √((4 - (-3))² + (5 - 5)²)

D = √(7² +0)

D = 7

8 0

4 years ago

In a triangle , the measure of the first angle is twice the measure of the second angle. The measure of the third angle is 80 mo

Flauer [41]

Answer:

25, 50, and 105.

Step-by-step explanation:

Let the first angle be A, the second angle be B, and the third angle be C.

First, the sum of the three angles in a triangle is 180. Thus:

$A+B+C=180$

We know that the measure of A is twice the measure of B. Thus:

$A=2B$

And the measure of C is 80 more than the measure of B. So:

$C=80+B$

Let's substitute A and C into the original equation:

$2B+B+80+B=180$

Now, let's solve for the second angle (B). Combine like terms:

$4B+80=180$

Subtract 80 from both sides:

$4B=100$

Divide both sides by 4:

$B=25$

So, the second angle is 25 degrees.

This means that the first angle is 2(25) or 50 degrees.

And the third angle is 80+25 or 105 degrees.

And we're done!

The angles are 25, 50, and 105.

8 0

3 years ago

Let X be a random variable with probability mass function P(X = 1) = 1 2 , P(X = 2) = 1 3 , P(X = 5) = 1 6 (a) Find a function g

Goryan [66]

The question is incomplete. The complete question is :

Let X be a random variable with probability mass function

P(X =1) =1/2, P(X=2)=1/3, P(X=5)=1/6

(a) Find a function g such that E[g(X)]=1/3 ln(2) + 1/6 ln(5). You answer should give at least the values g(k) for all possible values of k of X, but you can also specify g on a larger set if possible.

(b) Let t be some real number. Find a function g such that E[g(X)] =1/2 e^t + 2/3 e^(2t) + 5/6 e^(5t)

Solution :

Given :

$P(X=1)=\frac{1}{2}, P(X=2)=\frac{1}{3}, P(X=5)=\frac{1}{6}$