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dangina [55]
3 years ago
11

How to find the asymtope of a function

Mathematics
1 answer:
Darya [45]3 years ago
3 0
Asymptote at x = 3 and a horizontal asymptote at y = 1. The curves approach these asymptotes but never cross them. The method used to find the horizontal asymptote changes depending on how the degrees of the polynomials in the numerator and denominator of the function compare.
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PLEASE ANSWERRRRRRRRRRRRRRR
hoa [83]

Let T,S be the number of days spent at Tahoe and San Francisco, respectively.

We don't know the values of T and S yet, but we know that the holiday lasted 9 days:

T+S=9

We also know that each day spent in Tahoe costed 350 and each day spent in San Francisco costed 475. So, the total cost of the holiday is the sum of the number of days muliplied by their cost:

350T+475S=3650

If we put the two equations together, we have the system

\begin{cases}T+S=9\\350T+475S=3650\end{cases}

Which yields

S=4,\quad T=5

5 0
3 years ago
What is the answer to thus problem z=y-x
anastassius [24]
The only answers that are possible is z=y-x y=x+z or x=y-z
6 0
3 years ago
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Suppose the invertible function φ(x) has the domain (−5,11) and the range (−12,1).
Rom4ik [11]

Answer:

Range of \phi^{-1} is (−5,11).

Step-by-step explanation:

Given the invertible function Ф(x) which has the domain (−5,11) and the range (−12,1).

Invertible function is the function that inverses another function i.e if y=Ф(x) then x=g(y) where g is called the inverse of Ф and denoted by\phi^{-1}

Given Ф(x) the function whose domain is (−5,11) and range is (−12,1). Therefore, by definition of invertible function there exist a function g with domain (−12,1) and range (−5,11) which is called the inverse function denoted by \phi^{-1}

Hence, Range of \phi^{-1} is (−5,11)



3 0
3 years ago
Read 2 more answers
If you randomly select a beginner runner from the population have them run a 5k, what are the chances that they would finish it
Talja [164]

Answer:

I dont know I’m just trynna get points sorry

Step-by-step explanation:

8 0
3 years ago
Factor each experssion. 8x+16y
Neko [114]
8x + 16y = \boxed{\bf{8(x + 2y)}}
7 0
3 years ago
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