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3 years ago

Which of the following are solutions to the equation sinx cosx = 1/4? Check all that apply.

2 answers:

N76 [4]3 years ago

8 0

The solution is B. π/12+nπ

proof
sinx cosx = 1/4 is equivalent to 2 sinx cosx = 1/2 or sin2x =1/2
so 2x = arcsin(1/2) = π/6 + 2nπ, so x = π/12+nπ

Xelga [282]3 years ago

4 0

Answer:

Its B and D.

Step-by-step explanation:

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A person is standing 50 yards from the base of a building. The angle of elevation from the person to the top of the building is

Whitepunk [10]

Answer:

The height of the building is H = 11.65 yards

Step-by-step explanation:

Distance from the base of the building to the person = 50 yards

Angle of elevation = 25°

From Δ ABC

⇒ $\tan 25 = \frac{H}{25}$

⇒ $H = 25 \tan 25$

⇒ H = 11.65 yards

Therefore the height of the building is H = 11.65 yards

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2 years ago

Cancel membership how help

Mrrafil [7]

Answer:

U GOTS TO CLICK SETTINGS THEN CLICK CANCEL

Step-by-step explanation:

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3 years ago

A store buys cell phones from the manufacturer for $34.40 and marks them up by 85%. What is the sale price of the phones in the

Gnom [1K]

Answer:

$5.16

Step-by-step explanation:

34.40 divided by .85 is 29.24. Subtract the diffrence of 34,40 and 29.24 which is $5.16. Hope this helps :)

7 0

2 years ago

Suppose u and v are functions of x that are differentiable at x=0 and that u(0)=3, u'(0)= -4, v(0)= 2, v'(0)= -7. Find the value

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$\bf \cfrac{d}{dx}[u(x)\cdot v(x)]\implies \cfrac{du}{dx}\cdot v(x)+u(x)\cdot \cfrac{dv}{dx}\quad 
\begin{cases}
u(0)=3\qquad u'(0)=-4
\\\\
v(0)=2\qquad v'(0)=-7
\end{cases}
\\\\
\left[ \cfrac{du}{dx} \right]_{x=0}\cdot v(0)+u(0)\cdot \left[ \cfrac{dv}{dx} \right]_{x=0}$

so.. hmm pretty sure you know what that is

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3 years ago

Read 2 more answers

How can you make 2 cups of chocolate milk a gallon? I know that 32 = a gallon

const2013 [10]

Well you could use the equation 32=2x or 32=(2*x) but if you're looking for an answer that is other than turning this into an equation, then it would be impossible to find an answer. I hope this helped ^^

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2 years ago