<span>The amount P as a function of t (in years) is given by
P(t) = P0 (1 + r/n)^(t n)
So if n = 4, and r = 0.02, and P0 = 1000, then
P(t) = 1000 (1 + 0.02/4)^(4 t) = 1000 (1 + 0.005)^(4 t)
At the end of the first quarter, t = 1/4, so
P(1/4) = $1000 (1.005)^(1) = $1005
At the end of the second quarter, t = 1/2 , therefore
P(1/2) = $1000 (1.005)^(2) = $1000 (1.010025) = $1010.03
At the end of the third quarter , t = 3/4, therefore
P(3/4) = $1000 (1.005)^(3) = $1000 (1.015075125) = $1015.08
At the end of the year, t = 4, therefore
P(1) = $1000 (1.005)^4 = $1000 (1.020150500625) = $1020.15
As for the second question, after the first period (quarter),
the formula becomes
P = P0 (1.005)^1 = 1.005 P0
which is choice A. </span>
He simplified expression C because that is the only one that has only multiplications.
Answer:
Lose $0.05
Step-by-step explanation:
There are 38 possible spots on the roulette wheel (numbers 1 to 36, 0 and 00).
If the player can choose four numbers on single $1 bet, his chances of winning (W) and losing (L) are as follows:
The expected value of the bet is given by the probability of winning multiplied by the payout ($8), minus the probability of losing multiplied by the bet cost ($1)
On each bet, the player is expected to lose 5 cents ($0.05).
All you have to do is 19+5 because it is 5 less. 19 is 5 less than the kiwis. so 19+5= 24.
There is 24 boxes of kiwis
I don’t understand very much your question can you take it again so I could help
