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allsm [11]
3 years ago
10

The polynomial 6x2 + 37x – 60 represents an integer. Which expressions represent integer factors of 6x2 + 37x – 60 for all value

s of x? 3x – 4 and 2x + 15 3x + 4 and 2x – 15 2(x – 2) and 3(x + 5) 2(x + 2) and 3(x – 5)
Mathematics
2 answers:
nalin [4]3 years ago
8 0
3x – 4 and 2x + 15 is the correct answer
Charra [1.4K]3 years ago
3 0

Answer:

Its A on edg

Step-by-step explanation:

follow my ifunny "dankmemehistory"

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PLS help!!!!!!!!!!!!!!!!!!!!!!!!!!!!
kati45 [8]

The area of the figure is 104.52 sq inches

<h3>How to determine the area of the figure?</h3>

In the complete figure, we have:

1 Rectangle: Base = 8 in and Height = 6 in

2 semicircles: Diameter = 6 inches

The area of the figure is

Area = Area of rectangle + Sum of Areas of semicircles

This gives

Area = Base * Height + 2 * π(d/2)^2

This gives

Area = 8 * 6+ 2 * 3.14 * (6/2)^2

Evaluate

Area = 104.52

Hence, the area of the figure is 104.52 sq inches

Read more about areas at:

brainly.com/question/24487155

#SPJ1

7 0
2 years ago
GIVING BRAINLIEST!! HELP PLEASE!! you don't have to make it perfect. (no links/spam/or stealing points. i will report your accou
choli [55]
<h2>Answer:</h2>

C = 2πr

r = C/2π ...(1)

A = πr²

A = π(C/2π)² = πC²/4π²

A = C²/4π.

<u>Correct choice</u> - [A] A = C²/4π.

6 0
2 years ago
Can someone help me solve this ... please
lana66690 [7]

Answer:

t>28

Step-by-step explanation:

work is shown and pictured

4 0
3 years ago
Please help me with number 9! (Math)
Andrej [43]
Hi

I belive you add the top side (4) plus the bottom side (9.5) witch would equal 13.5 times the hieght (3) equals 40.5 divided by 2 equals 20.25. the area is 20.25ft squared

another way to do it
4+9.5= 13.5
13.5×3= 40.5
40.5÷2= 20.25ft
8 0
3 years ago
The Sky Ranch is a supplier of aircraft parts. Included in stock are 6 altimeters that are correctly calibrated and two that are
almond37 [142]

Answer:

For x = 0, P(x = 0) = 0.35

For x = 1, P(x = 1) = 0.54

For x = 2, P(x = 2) = 0.11

For x = 3, P(x = 3) = 0

Step-by-step explanation:

We are given that the Sky Ranch is a supplier of aircraft parts. Included in stock are 6 altimeters that are correctly calibrated and two that are not. Three altimeters are randomly selected, one at a time, without replacement.

Let X = <u><em>the number that are not correctly calibrated.</em></u>

Number of altimeters that are correctly calibrated = 6

Number of altimeters that are not correctly calibrated = 2

Total number of altimeters = 6 + 2 = 8

(a) For x = 0: means there are 0 altimeters that are not correctly calibrated.

This means that all three selected altimeters are correctly calibrated.

Total number of ways of selecting 3 altimeters from a total of 8 = ^{8}C_3

The number of ways of selecting 3 altimeters from a total of 6 altimeters that are correctly calibrated = ^{6}C_3

So, the required probability = \frac{^{6}C_3}{^{8}C_3}  

                                              = \frac{20}{56}  = <u>0.35</u>

(b) For x = 1: means there is 1 altimeter that is not correctly calibrated.

This means that from three selected altimeters; 1 is not correctly calibrated and 2 are correctly calibrated.

Total number of ways of selecting 3 altimeters from a total of 8 = ^{8}C_3

The number of ways of selecting 2 correctly calibrated altimeters from a total of 6 altimeters that are correctly calibrated = ^{6}C_2

The number of ways of selecting 1 not correctly calibrated altimeters from a total of 2 altimeters that are not correctly calibrated = ^{2}C_1

So, the required probability = \frac{^{6}C_2 \times ^{2}C_1 }{^{8}C_3}  

                                                = \frac{30}{56}  = <u>0.54</u>

(c) For x = 2: means there is 2 altimeter that is not correctly calibrated.

This means that from three selected altimeters; 2 are not correctly calibrated and 1 is correctly calibrated.

Total number of ways of selecting 3 altimeters from a total of 8 = ^{8}C_3

The number of ways of selecting 1 correctly calibrated altimeters from a total of 6 altimeters that are correctly calibrated = ^{6}C_1

The number of ways of selecting 2 not correctly calibrated altimeters from a total of 2 altimeters that are not correctly calibrated = ^{2}C_2

So, the required probability = \frac{^{6}C_1 \times ^{2}C_2 }{^{8}C_3}  

                                                = \frac{6}{56}  = <u>0.11</u>

(d) For x = 3: means there is 3 altimeter that is not correctly calibrated.

This case is not possible, so this probability is 0.

6 0
3 years ago
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