It’s 2x the size I believe :)
f(x) > 0 - I and II quadrant
f(x) < 0 - III and IV quadrant
Look at the picture.
A. F(x) < 0 on the interval x < 0. TRUE
B. F (x) > 0 on the interval x <0. FALSE
C. F (x) < 0 on the interval 0 < x < 1. TRUE
D. F (x) > 0 on the interval 0 < x < 1. FALSE
E. F (x) < 0 on the interval 1 < x < 3. FALSE
F. F (x) > 0 on the interval 1 < x < 3. TRUE
G. F (x) < 0 on the interval x > 3. TRUE
H. F (x) > 0 on the interval x > 3. FALSE
Answer:
A) Mean = 135 Variance = 62 Standard Deviation = 8
Step-by-step explanation:
Given that :
Proportion (p) = 54%
Sample size (n) = 250
Using Normal approximation :
Mean = np
Mean = 250 * 0.54 = 135
Variance = npq ; q = 1 - p = 1 - 0.54 = 0.46
Variance = (250 * 0.54 * 0.46) = 62.1 = 62
Standard deviation = √variance = √62.1
Standard deviation = 7.8803553 = 8
Answer:
36
Step-by-step explanation:
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