Answer: The frequency of brown beetles is 0.32.
Explanation: The frequency of A1 allele is 0.8. As p+q=1, or the sum of dominant and recessive frequencies equals 1 or 100%:
1 - 0.8 = 0.2
In Hardy-Weinberg principle,
2pq represents the frequency of heterozygote individuals, so:
genotype A1A2 = 2*0.8*0.2 = 0.32.
Thus, the frequency of brown beetles (A1A2) in the population is 0.32.
We just finished this unit, and The answer is A.
B explained is that idek I just need points
It is true that it is possible for a population to not evolve for a while.
There is something called the Hardy-Weinberg theorem, which characterizes the distributions of genotype frequencies in populations that are not evolving.
There are 5 Hardy-Weinberg assumptions:
- no mutation
- random mating
- no gene flow
- infinite population size
- and no selection (natural nor forced).
You can see that some of these are kinda extreme and really hard to get, but with approximations, we can work.
For example, instead of an "infinite population size" we have enough with a really large population, such that genetic drift is negligible.
Concluding, yes, it is possible (but really difficult) for a population to not evolve for a while (at least, in nature), as long as the 5 assumptions above are met.
If you want to learn more, you can read:
brainly.com/question/19431143
During telophase, membrane-enclosed vesicles derived from the Golgi apparatus migrate to the center of the cell where the metaphase plate used to be and fuse to form a cell plate. Eventually, the growing cell plate fuses with the existing plasma membrane, producing two daughter cells, each with its own plasma membrane.
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