Answer: The probability that it will break down in the next 21 days is 0.777
Step-by-step explanation:
Let the random variable x represent
time between breakdowns of a generator
Given that mean = 14 days,
Decay parameter, m = 1/14
The probability density function for exponential distribution is expressed as
F(x) = me-mx
It becomes
f(x) = 1/14e-(x × 1/14)
P(X < x) = 1 - e- mx
The probability that it will break down in the next 21 days is expressed as
P(x ≤ 21) = P(x < 21)
Therefore,
P(x < 21) = 1 - e-(1/14 × 21)
= 1 - e-1.5
= 1 - 0.223 = 0.777
P(x ≤ 21) = 0.777
Answer:
π/3
Step-by-step explanation:
-5π/3 is a co terminal of 2π-5π/3= (6π-5π)/3=π/3
The solution is 3x^2
For solve the equation need to use the limit. I don’t know if you already study it