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3 years ago

26,143,062 expanded form

Mathematics

2 answers:

IrinaVladis [17]3 years ago

5 0

20,000,000 + 6,000,000 + 100,000 + 40,000 + 3,000 + 60 + 2

Keith_Richards [23]3 years ago

5 0

20,000,000+6,000,000+100,000+40,000+3,000+60+2. Hope this helps.

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SOLVE. 1/5x=-10 <img src="https://tex.z-dn.net/?f=1%20%5Cdiv%205x%20%3D%20%20-%2010" id="TexFormula1" title="1 \div 5x =

Sladkaya [172]

Answer: X = -50

Step-by-step explanation:

1. 1/5x = -10

1/5x = -10

2.Multiply by 1

3.Multiply all terms by the same value to eliminate fraction denominators.

4.Simplfiy

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3 years ago

Can you please help me.

scoundrel [369]

Is this homework?

You can always go back in the lesson what you have learned and or ask your parents.

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3 years ago

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What is 4^12 x 125^7? Express your answer in scientific notation

lianna [129]

Answer:

8×10^21

Step-by-step explanation:

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3 years ago

/PLEASE/ Help!!

Lubov Fominskaja [6]

The answer usually question what does this question do you think Association

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3 years ago

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Complete the assignment on a separate sheet of paper Please attach pictures of your work.

Irina18 [472]

Answer:

TO FIND :-

Length of all missing sides.

FORMULAES TO KNOW BEFORE SOLVING :-

$\sin \theta = \frac{Side \: opposite \: to \: \theta}{Hypotenuse}$
$\cos \theta = \frac{Side \: adjacent \: to \: \theta}{Hypotenuse}$
$\tan \theta = \frac{Side \: opposite \: to \: \theta}{Side \: adjacent \: to \: \theta}$

SOLUTION :-

1) θ = 16°

Length of side opposite to θ = 7

Hypotenuse = x

$=> \sin 16 = \frac{7}{x}$

$=> \frac{7}{x} = 0.27563......$

$=> x = \frac{7}{0.27563....} = 25.39568.....$ ≈ 25.3

2) θ = 29°

Length of side opposite to θ = 6

Hypotenuse = x

$=> \sin 29 = \frac{6}{x}$

$=> \frac{6}{x} = 0.48480......$

$=> x = \frac{6}{0.48480....} = 12.37599.....$ ≈ 12.3

3) θ = 30°

Length of side opposite to θ = x

Hypotenuse = 11

$=> \sin 30 = \frac{x}{11}$

$=> \frac{x}{11} = 0.5$

$=> x = 0.5 \times 11 = 5.5$

4) θ = 43°

Length of side adjacent to θ = x

Hypotenuse = 12

$=> \cos 43 = \frac{x}{12}$

$=> \frac{x}{12} = 0.73135......$

$=> x = 12 \times 0.73135.... = 8.77624....$ ≈ 8.8

5) θ = 55°

Length of side adjacent to θ = x

Hypotenuse = 6

$=> \cos 55 = \frac{x}{6}$

$=> \frac{x}{6} = 0.57357......$

$=> x = 6 \times 0.57357.... = 3.44145....$ ≈ 3.4

6) θ = 73°

Length of side adjacent to θ = 8

Hypotenuse = x

$=> \cos 73 = \frac{8}{x}$

$=> \frac{8}{x} = 0.29237......$

$=> x = \frac{8}{0.29237.....} = 27.36242.....$ ≈ 27.3

7) θ = 69°

Length of side opposite to θ = 12

Length of side adjacent to θ = x

$=> \tan 69 = \frac{12}{x}$

$=> \frac{12}{x} = 2.60508......$

$=> x = \frac{12}{2.60508....} = 4.60636....$ ≈ 4.6

8) θ = 20°

Length of side opposite to θ = 11

Length of side adjacent to θ = x

$=> \tan 20 = \frac{11}{x}$

$=> \frac{11}{x} = 0.36397......$

$=> x = \frac{11}{0.36397....} =30.22225....$ ≈ 30.2

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2 years ago