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PtichkaEL [24]
4 years ago
9

Tickets to the concert were 2.50 for adults and 1.00 for students. 1,200 was collected and 750 tickets were sold.

Mathematics
1 answer:
Minchanka [31]4 years ago
3 0

Answer:

I'm assuming you want to know the amount of child and adult tickets sold. 450 student tickets were sol, and 300 adult tickets.

Step-by-step explanation:

Solve for the first variable in one of the equations, then substitute the result into the other equation.

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Answer:

if we are talking about cubit feet then 478.753

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Use angle relationships to complete the top equation. Then, solve for x and find the measure of both angles.
VashaNatasha [74]
7x + 5 = 180
x = 25
6x = 150
x + 5 = 30

7 0
3 years ago
Solve x2 + 10x + 12 = 36 for x. x = â12 or x = 2 x = â11 or x = 1 x = â2 or x = 12 x = â1 or x = 11
meriva
The answer is number A: â12 or x = 2
6 0
3 years ago
If z1= 3+3i and z2=7(cos(5pi/9) + i sin (5pi/9)), then z1/z2= blank
mixas84 [53]

z1=\stackrel{a}{3}+\stackrel{b}{3}i~~ \begin{cases} r = \sqrt{a^2+b^2}\\ r = \sqrt{18}\\[-0.5em] \hrulefill\\ \theta =\tan^{-1}\left( \frac{b}{a} \right)\\ \theta =\frac{\pi }{4} \end{cases}~\hfill z1=\sqrt{18}\left[\cos\left( \frac{\pi }{4} \right) i\sin\left( \frac{\pi }{4} \right) \right] \\\\[-0.35em] ~\dotfill

\cfrac{z1}{z2}\implies \cfrac{\sqrt{18}\left[\cos\left( \frac{\pi }{4} \right) i\sin\left( \frac{\pi }{4} \right) \right]} {7\left[\cos\left( \frac{5\pi }{9} \right) i\sin\left( \frac{5\pi }{9} \right) \right]} \\\\[-0.35em] ~\dotfill\\\\ \qquad \textit{division of two complex numbers} \\\\ \cfrac{r_1[\cos(\alpha)+i\sin(\alpha)]}{r_2[\cos(\beta)+i\sin(\beta)]}\implies \cfrac{r_1}{r_2}[\cos(\alpha - \beta)+i\sin(\alpha - \beta)] \\\\[-0.35em] ~\dotfill

\cfrac{z1}{z2}\implies \cfrac{\sqrt{18}}{7}\left[\cos\left( \frac{\pi }{4}-\frac{5\pi }{9} \right)+i\sin\left( \frac{\pi }{4}-\frac{5\pi }{9} \right) \right] \\\\\\ \cfrac{\sqrt{18}}{7}\left[\cos\left( \frac{-11\pi }{36} \right) +i\sin\left( \frac{-11\pi }{36} \right) \right]\implies \cfrac{\sqrt{18}}{7}\left[\cos\left( \frac{83\pi }{36} \right) +i\sin\left( \frac{83\pi }{36} \right) \right] \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \cfrac{z1}{z2}\approx 0.348~~ + ~~0.496i~\hfill

6 0
3 years ago
You are designing a container in the shape of a cylinder. The radius is 6 inches. You want the container to hold at least 324π c
natta225 [31]

By definition, the volume of a cylinder is given by:

V =\pi r^2h

Where,

r: cylinder radius

h: cylinder height

From here, we clear the height.

We have then:

h = \frac{V}{\pi r^2 }

Then, replacing values we have:

h = \frac{324\pi }{\pi 6^2 }

h = 9 inches

Answer:

The least possible height of the container is 9 inches.

4 0
3 years ago
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