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Bad White [126]
3 years ago
6

PLS HELP ASAP PLSSSS!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
Lunna [17]3 years ago
5 0

Answer:

2800 in^3

Step-by-step explanation:

Calculate the volume as normal, but take 1/10 of the result. Since volume is length*width*height, we have 50*28*20 which is 28000. 1/10 of that is 2800. So the volume when scaled down by a factor of 1/10 is 2800 in^3

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When you subtract one square number from another the answer is 3 what are the two square numbers
dimulka [17.4K]
The numbers are 1 and 2

1 squared = 1 because 1 x 1 = 1
2 squared = 4 because 2 x 2 = 4

4 - 1 = 3
5 0
3 years ago
A circle has a radius of 3 feet. What is the circumference of a bigger circle if the scale factor of the smaller to bigger is 4:
Vaselesa [24]
Big/small=4/7

r1/r2=4/7 where  r1, r2 are radius of a big and small circles respectively

r1/3=4/7

r1=12/7

circumference of a big circle is2πr1=2π*12/7=24π/7 cm
7 0
3 years ago
Connor bought a pack of 4 notebooks for<br> $8.20. What was the unit price? please explain
Mamont248 [21]

Answer:

$2.05

Step-by-step explanation:

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$2.05

3 0
3 years ago
Integration of (cosec^2 x-2005)÷cos^2005 x dx is
kondor19780726 [428]
We are asked in the problem to evaluate the integral of <span>(cosec^2 x-2005)÷cos^2005 x dx. The function is an example of a complex function with a degree that is greater than one and that uses special rules to integrate the function via the trigonometric functions. For example, we integrate 
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Then, 
</span><span>∫tanx<span>sec(<span>n−3)</span></span>x(secxtanx)dx=<span><span>tanx<span>sec(<span>n−2)</span></span>x/(</span><span>n−2)</span></span>−<span>1/(<span>n−2)I
we can then integrate the function by substituting n by 3.

On the first term csc^2 2005x / cos^2005 x we can use the trigonometric identity csc^2 x = 1 + cot^2 x to simplify the terms</span></span></span>
7 0
3 years ago
Simplify 5^2 x 5^4<br> A. 5^6 <br> B. 5^2 <br> C. 5 x 8 <br> D. 5^8
Romashka [77]

Answer:

A

Step-by-step explanation:

Both equal 15,625

5 0
3 years ago
Read 2 more answers
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