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spin [16.1K]
3 years ago
9

A network administrator wants to increase the speed and fault tolerance of a connection between two network switches. To achieve

this, which protocol should the administrator use?
Computers and Technology
2 answers:
Sedaia [141]3 years ago
5 0

DLP stands for Data Loss Prevention

The process of stealing data loss is prevented by “monitoring, detecting and blocking”. This avoids data leaks during “network traffic – in motion”, “in use – endpoint action” and “at rest – data storage”. The term “data loss and data leaks” are same and it can be used interchangeably.

There are various other technical terminologies associated with data leak are “ILDP – Information Leak Detection and Protection”, “ILP – Information Leak Protection”, “CMF – Content Monitoring and Filtering”, “IPC – Information and Protection Control”, “EPS – Extrusion prevent system”, etc.

Contact [7]3 years ago
5 0

Answer:

transfer one of network's

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A data type consisting of numbers, letters and symbols is a _____.
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4 0
2 years ago
Write a program that allows the user to enter the last names of five candidates in a local election and the number of votes rece
amm1812

Answer:

a= input("Enter the last name of first candidate: ")

aVotes= int(input("Enter Number of votes cast for "+ a + ": "))

b= input("Enter the last name of second candidate: ")

bVotes= int(input("Enter Number of votes cast for "+ b + ": "))

c= input("Enter the last name of third candidate: ")

cVotes= int(input("Enter Number of votes cast for "+ c + ": "))

d= input("Enter the last name of fourth candidate: ")

dVotes = int(input("Enter Number of votes cast for "+ d + ": "))

e= input("Enter the last name of fifth candidate: ")

eVotes = int(input("Enter Number of votes cast for "+ e + ": "))

votes= [aVotes,bVotes,cVotes,dVotes,eVotes]

aPercent= (round((aVotes/sum(votes))*100, 2))

bPercent= (round((bVotes/sum(votes))*100, 2))

cPercent= (round((cVotes/sum(votes))*100, 2))

dPercent= (round((dVotes/sum(votes))*100, 2))

ePercent= (round((eVotes/sum(votes))*100, 2))

print( a, ":", aVotes,"Votes", aPercent,"%")

print( b, ":", bVotes,"Votes", bPercent,"%")

print( c, ":", cVotes,"Votes", cPercent,"%")

print( d, ":", dVotes,"Votes", dPercent,"%")

print( e, ":", eVotes,"Votes", ePercent,"%")

winner= max(votes)

if winner==aVotes:

   print(a," is the Winner")

elif winner==bVotes:

   print(b," is the Winner")

elif winner==cVotes:

   print(c," is the Winner")

elif winner==dVotes:

   print(d," is the Winner")

elif winner==eVotes:

   print(e," is the Winner")

else:

   None

Explanation:

  • First section

<em> a= input("Enter the last name of first candidate: ") </em>

<em>aVotes= int(input("Enter Number of votes cast for "+ a + ": ")) </em>

<em>b= input("Enter the last name of second candidate: ") </em>

<em>bVotes= int(input("Enter Number of votes cast for "+ b + ": ")) </em>

<em>c= input("Enter the last name of third candidate: ") </em>

<em>cVotes= int(input("Enter Number of votes cast for "+ c + ": ")) </em>

<em>d= input("Enter the last name of fourth candidate: ") </em>

<em>dVotes = int(input("Enter Number of votes cast for "+ d + ": ")) </em>

<em>e= input("Enter the last name of fifth candidate: ") </em>

<em>eVotes = int(input("Enter Number of votes cast for "+ e + ": ")) </em>

Collects the last name and the number of  votes cast

  • Second section

<em>votes= [aVotes,bVotes,cVotes,dVotes,eVotes] </em>

<em />

places all the votes in a list.

The reason for this is to allow us use the "sum function" and "max function", to get the sum of all the votes.

  • Third section

<em>aPercent= (round((aVotes/sum(votes))*100, 2)) </em>

<em>bPercent= (round((bVotes/sum(votes))*100, 2)) </em>

<em>cPercent= (round((cVotes/sum(votes))*100, 2)) </em>

<em>dPercent= (round((dVotes/sum(votes))*100, 2)) </em>

<em>ePercent= (round((eVotes/sum(votes))*100, 2)) </em>

calculates the percentage of all the votes cast for the individual candidates

  • Fourth section

<em>print( a, ":", aVotes,"Votes", aPercent,"%") </em>

<em>print( b, ":", bVotes,"Votes", bPercent,"%") </em>

<em>print( c, ":", cVotes,"Votes", cPercent,"%") </em>

<em>print( d, ":", dVotes,"Votes", dPercent,"%") </em>

<em>print( e, ":", eVotes,"Votes", ePercent,"%") </em>

prints out the candidates name, number of votes received and the percentage

  • Fifth section

winner= max(votes)

gets the maximum votes cast

  • Sixth Section

if winner==aVotes:

   print(a," is the Winner")

elif winner==bVotes:

   print(b," is the Winner")

elif winner==cVotes:

   print(c," is the Winner")

elif winner==dVotes:

   print(d," is the Winner")

elif winner==eVotes:

   print(e," is the Winner")

else:

   None

uses if statements to compare the maximum votes with the votes gotten by all the candidates to get a winner

4 0
4 years ago
Łatwiej pokonać każdą trudność, gdy dąży się do swojego wymarzonego celu. Czy zgadzasz się z tym poglądem? W uzasadnieniu odwoła
Anna [14]

Answer:

Yes.

Explanation:

Your question is not clear. However, I inferred you need the clearer rendering of the question. It reads;

It is easier to overcome any difficulty when pursuing your dream goal. Do you agree with this view? In the justification, refer to compulsory reading and to another literary work.

6 0
3 years ago
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Inessa05 [86]

1. OR

2. AND

...........................................

6 0
3 years ago
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