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3 years ago

Introduction or background of corporal punishment in schools

Computers and Technology

1 answer:

tensa zangetsu [6.8K]3 years ago

3 0

Answer:

Corporal punishment is a discipline method in which a supervising adult, such as a teacher, deliberately inflicts pain upon a child in response to a child's unacceptable behavior or inappropriate language. The goals of this type of punishment are usually to halt the offense immediately, prevent it from happening again, and set an example for others.

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How do you answer questions

Vera_Pavlovna [14]

Answer:

like this

Explanation:

<h3>you click answer and then<u><em> boom</em></u></h3>

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3 years ago

Please help me !!

gavmur [86]

e. uhmmm

19+21=30

like....

easy.

What grade class is this? I wanna do it cause it easy AFef

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3 years ago

Given the following adjacency matrix, what is the approximate rank vector after one iteration of the power iteration method (use

ValentinkaMS [17]

Note: The matrix referred to in the question is: $M = \left[\begin{array}{ccc}1/2&1/3&0\\1/2&1/3&0\\0&1/3&1\end{array}\right]$

Answer:

a) [5/18, 5/18, 4/9]'

Explanation:

The adjacency matrix is $M = \left[\begin{array}{ccc}1/2&1/3&0\\1/2&1/3&0\\0&1/3&1\end{array}\right]$

To start the power iteration, let us start with an initial non zero approximation,

$X_o = \left[\begin{array}{ccc}1\\1\\1\end{array}\right]$

To get the rank vector for the first Iteration:

$X_1 = MX_0$

$X_1 = \left[\begin{array}{ccc}1/2&1/3&0\\1/2&1/3&0\\0&1/3&1\end{array}\right]\left[\begin{array}{ccc}1\\1\\1\end{array}\right] \\\\X_1 = \left[\begin{array}{ccc}5/6\\5/6\\4/3\end{array}\right]\\$

Multiplying the above matrix by 1/3

$X_1 = \left[\begin{array}{ccc}5/18\\5/18\\4/9\end{array}\right]$

8 0

3 years ago

Where can you access email accounts on your windows 7 computer in order to modify current accounts or create new ones?

Mademuasel [1]

I'll create new ones because just for me, its so hassle

8 0

3 years ago

You also learn in class that one kilobyte of computer memory will hold about 2/3 of a page of typical text (without formatting).

Travka [436]

Answer:

The flashdrive can hold 35389 400-pages-books

Explanation:

If $\frac{2}{3}$ of a page occupies 1 kB of memory, we can calculate how much memory a book will take

$2/3kB=1 page\\ x kB=400 pages\\266.67 kB=400 pages$

Now that we know that a book average file size is about 266,67 kB, we calculate how many of them can a 9 GB flash drive hold.

To do the calculation, we have to know how many kilobytes are in 9 gigabytes.

There is 1024 kilobytes in a megabyte, and 1024 megabytes in a gigabyte, so:

$Memory_{in _kilobytes}^{} =1024\frac{kilobytes}{megabytes} *1024\frac{megabytes}{gigabytes}*9=9437184 kilobytes$

Finally, knowing the average file size of a book and how much memory in kilobytes the 9 GB flash drive holds, we calculate how many books can it hold.

$Books=\frac{Flash drive memory}{Filesize of a book} =\frac{9437184kilobytes}{266.67\frac{kilobytes}{book} } =35389,4 books$

The flashdrive can hold 35389 400-pages-books, or 14155776 pages of typical text.

8 0

4 years ago