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iren [92.7K]
3 years ago
9

matlab Write a function that iteratively appends random 1's and 0's to an array to form a binary number. The function returns th

e binary result when it's decimal equivalent is larger than the input number. [outArray] = potd11(inputNumber)
Computers and Technology
1 answer:
egoroff_w [7]3 years ago
7 0

Answer:

function [outArray] = potd11(inputNumber)

outArray = [0];

d = 0;

while d < inputNumber

outArray = [outArray, randi([0,1])];

d = sum(outArray .* (2.* ones(1, numel(outArray))).^(numel(outArray)-1 :-1:0));

end

end

Explanation:

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Answer:

In Python:

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while True:

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       print("Error: No comma in string")

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   else:

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Explanation:

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entry = input("Sentence: ")

The following loop is repeated until the user enters a valid entry

while True:

This is executed if the number of commas is 0

<em>    if entry.count(",") == 0:</em>

<em>        print("Error: No comma in string")</em>

<em>        entry = input("Sentence: ")</em>

This is executed if the number of commas is more than 1

<em>    elif entry.count(",") > 1:</em>

<em>        print("Error: Too many comma in input")</em>

<em>        entry = input("Sentence: ")</em>

This is executed if the number of commas is 1

   else:

This calculates the next index after the comma

       ind = entry.index(',')+1

This checks if the character after the comma is a number

       if entry[ind].isnumeric() == False:

If it is not a number, the print statement is executed

<em>            print("Comma not followed by an integer")</em>

<em>            entry = input("Sentence: ")</em>

If otherwise, the loop is exited

<em>        else:</em>

<em>            break</em>

This prints valid input, when the user enters a valid string

print("Valid Input")

Note that: entry = input("Sentence: ") <em>is used to get input</em>

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