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Snowcat [4.5K]
3 years ago
8

5 meters in 0.1 second

Mathematics
2 answers:
viva [34]3 years ago
7 0

What is the question idg

Irina-Kira [14]3 years ago
6 0
I don’t get what you’re trying to say
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1: 40% of the students on a field trip love the museum. If there are 20 students on the field trip, how many love the museum?
Allisa [31]

20 students times 40% of them is 20 times 0.40, which is 8

499 divided by the sale price, 424.13

1.1765, or when rounded, 1.18%

1. 8 students

2. 1.18%

5 0
3 years ago
Which is a factor of x^2-9x+14?<br> A. X-9<br> B. X-2<br> C. X+5<br> D. X+7
sukhopar [10]

Answer : B

x^2-9x+14

Lets factor x^2-9x+14

We find out two factors whose product is +14 and sum is -9

Two factors are -2  and -7, we split the middle term -9x using -2  and -7

x^2-2x-7x+14

Group first two terms and last two terms

Then factor out GCF from each term

(x^2-2x)(-7x+14)

x(x-2)-7(x-2)

(x-2)(x-7)

so x-2 is one of the factor

3 0
3 years ago
I’m lost please help
vagabundo [1.1K]

Answer:

See proof below

Step-by-step explanation:

Two triangles are said to be congruent if one of the 4 following rules is valid

  1. The three sides are equal
  2. The three angles are equal
  3. Two angles are the same and a corresponding side is the same
  4. Two sides are equal and the angle between the two sides is equal

Let's consider the two triangles ΔABC and ΔAED.

ΔABC sides are AB, BC and AC

ΔAED sides are AD, AE and ED

We have AE = AC and EB = CD

So AE + EB = AC + CD

But AE + EB = AB and AC+CD = AD

We have

AB of ΔABC  = AD of ΔAED

AC of ΔABC =  AE of ΔAED

Thus two sides the these two triangles. In order to prove that the triangles are congruent by rule 4, we have to prove that the angle between the sides is also equal. We see that the common angle is ∡BAC = ∡EAC

So  triangles ΔABC and ΔAED are congruent

That means all 3 sides of these triangles are equal as well as all the angles

Since BC is the third side of ΔABC and ED the third side of ΔAED, it follows that

BC = ED  Proved

5 0
2 years ago
Find the area of a regular octagon with a side length of 10cm
Dmitriy789 [7]

Steps:

Shape: Regular octagon

Solved for area

Side= 10cm

Formula: A=2(1√+2)a2

Round to the nearest tenth = 482.8

Description:

Using the formula for the area of Regular octagon ( A=2(1√+2)a2) We have to calculate the side length that is 10 cm. Your answer will equal as A≈482.84cm² after you calculate. Since it says to round to the nearest tenth your answer will come as 482.8.

Answer: A≈482.84cm²

Round to the nearest tenth = 482.8

Please mark brainliest

<em><u>Hope this helps.</u></em>

6 0
3 years ago
Due today plz help me i am very desprate don’t just answer for points
STALIN [3.7K]
1) 43
2) 84
3) 80
4) 53
5) 58
6) 47
hope this helps
8 0
3 years ago
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