Six fingered offspring are formed from normal fingered parents
2 answers:
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Answer:
Bb X bb
Explanation:
- It is given that the allele B for the black coat is dominant over allele b for a brown coat.
- A dominant allele always leads to the expression of the dominant trait in the heterozygous condition.
- When a black and brown horse is crossed as given in the question and the result is a brown foal, then the genotype of the brown foal must be bb as the brown coat is a recessive trait.
- Since each parent contributes one allele each for a given gene, the black horse must have b allele, and hence must be heterozygous Bb.
- The cross is shown in the punnett square.
