I don't quite understand the log form you have, but the way to solve logarithms is to convert them to exponents.
log(b) a = c
b^c = a
So....
log(b) x = y
b^y = x
Does that make sense?
we will select each options and find zeros
(a)

for finding x-intercept , we can set g(x)=0
and then we can solve for x

now, we can factor it

we get

so, this is TRUE
(b)

we can set it to 0
and then we can solve for x

we get

so, this is FALSE
(c)

we can set it to 0
and then we can solve for x




so, this is TRUE
(d)

now, we can set it to 0
and then we can solve for x


so, this is TRUE
(e)
we have

now, we can set it to 0
and then we can solve for x



so, this is FALSE
Answer:
Malcolm is showing evidence of gambler's fallacy.
This is the tendency to think previous results can affect future performance of an event that is fundamentally random.
Step-by-step explanation:
Since each round of the roulette-style game is independent of each other. The probability that 8 will come up at any time remains the same, equal to the probability of each number from 1 to 10 coming up. That it has not come up in the last 15 minutes does not increase or decrease the probability that it would come up afterwards.
Answer: just multiply 9 and y together: 9 x y
So, pretend this is your x-axis and y-axis:
I
I
(-2,7) • I
I
I • (2, 5)
I
I
I
I
_________________I____________________
I
I
I
TO GET FROM POINT (-2, 7) TO POINT (2, 5), WE MOVE DOWN 2 AND OVER 4, SO THE SLOPE IS -1/2. IF WE FOLLOW THAT SLOPE AND MOVE DOWN 1 AND OVER 2 FROM THE FIRST POINT OF (-2, 7), WE WILL LAND ON A POINT LOCATED AT (0, 6), WHICH WOULD BE THE "Y-INTERCEPT". WE WERE JUST ABLE TO CALCULATE THE SLOPE OF THE LINE AND THEN USE THE SLOPE TO FIND THE INTERCEPT. SO, THE "SLOPE-INTERCEPT" FORM OF THE EQUATION FOR THIS LINE IS:
y = -1/2x + 6
TO RE-WRITE THIS IN STANDARD FORM, WE JUST WANT TO MOVE THE X VARIABLE OVER TO THE LEFT WITH THE Y VARIABLE, SO:
y = -1/2x + 6
+1/2x + 1/2x
1/2x + y = 6 .... and that is your answer!